Accelerating Proton: Calculating Speed and Kinetic Energy

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SUMMARY

The discussion focuses on calculating the final speed and kinetic energy increase of a proton being accelerated at 2.0x1015 m/s2 with an initial speed of 2.4x107 m/s over a distance of 2.5 cm. Participants emphasize using the kinematic equation v2 = v02 + 2a(Δx) to find the final velocity and the kinetic energy formula KE = 0.5mv2 to calculate the increase in kinetic energy. The change in kinetic energy is determined by ΔKE = m(vf2 - vi2).

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with kinematic equations, specifically SUVAT equations
  • Knowledge of kinetic energy calculation (KE = 0.5mv2)
  • Basic algebra for rearranging equations
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  • Study the derivation and application of SUVAT equations in physics
  • Learn how to calculate kinetic energy changes in particle physics
  • Explore advanced topics in classical mechanics related to particle acceleration
  • Review examples of problems involving force, mass, and acceleration
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Homework Statement



A proton (mass m = 1.67x10^-27 kg) is being accelerated along a straight line at 2.0x10^15 m/s^2 in a machine. The proton has an initial speed of 2.4x10^7 m/s and travels 2.5 cm.

(a) What is its speed?

(b) What is the increase in its kinetic energy?

The Attempt at a Solution



Is it ok to have no idea where to begin?

I know F=ma, and that V=Vo+1/2at... but I can't see how that helps.

Help me begin?
 
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wadesweatt said:
1. Homework Statement

A proton (mass m = 1.67x10^-27 kg) is being accelerated along a straight line at 2.0x10^15 m/s^2 in a machine. The proton has an initial speed of 2.4x10^7 m/s and travels 2.5 cm.

(a) What is its speed?

(b) What is the increase in its kinetic energy?

3. The Attempt at a Solution

Is it ok to have no idea where to begin?

I know F=ma, and that V=Vo+1/2at^2... but I can't see how that helps.

Help me begin?

You just need two equations.

Kinetic energy.

And an equation that relates Velocity, distance and acceleration.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 
no lowly pion you are wrong what he needs is the other SUVAT equations namely.

S=0.5(u+v)t then rearrange to get V
(u is intitial velocity)

then you put that into the the kenetic energy equation

KE=0.5mv^2

then you have got your anser
 
ffrog said:
no lowly pion you are wrong what he needs is the other SUVAT equations namely.

S=0.5(u+v)t then rearrange to get V
(u is intitial velocity)

then you put that into the the kenetic energy equation

KE=0.5mv^2

then you have got your anser

And what is the time the proton is in the machine?
 
LowlyPion said:
You just need two equations.

Kinetic energy.

And an equation that relates Velocity, distance and acceleration.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2


So, using v^2 = v_0^2 + 2a(Delta x), I can find the final velocity I think. For the delta x part, would it be (2.5 - 0)?

And can I use KE= 1/2mv^2 to find the kinetic energy? If so, wouldn't I use the final velocity found in part a for "v"?

Thanks.
 
wadesweatt said:
So, using v^2 = v_0^2 + 2a(Delta x), I can find the final velocity I think. For the delta x part, would it be (2.5 - 0)?

And can I use KE= 1/2mv^2 to find the kinetic energy? If so, wouldn't I use the final velocity found in part a for "v"?

Thanks.

Yes the V2 = Vi2 + 2ax should do you well.

Part b) is looking for ΔKE. So you are needing to calculate the final KE and subtract the initial.
 
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LowlyPion said:
Yes the V2 = Vi2 + 2ax should do you well.

Part b) is looking for ΔKE. So you are needing to calculate the final KE and subtract the initial.

Ahhhh so I do change in KE=m(v_f)^2 - m(v_i)^2 , right?
 
wadesweatt said:
Ahhhh so I do change in KE=m(v_f)^2 - m(v_i)^2 , right?

Half right anyway.

... i.e don't forget the 1/2.
 
LowlyPion said:
Half right anyway.

... i.e don't forget the 1/2.

haha yes! I knew that I was just typing in a hurry.

Thanks.
 

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