Accelerating Proton: Calculating Speed and Kinetic Energy

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Homework Help Overview

The discussion revolves around a physics problem involving a proton being accelerated in a machine. The problem requires calculating the final speed and the increase in kinetic energy of the proton given its mass, initial speed, acceleration, and distance traveled.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express uncertainty about how to start the problem, referencing fundamental equations like F=ma and kinematic equations. There are discussions about using specific equations to relate velocity, distance, and acceleration, as well as the kinetic energy formula.

Discussion Status

Participants are exploring various approaches to solve the problem, with some suggesting specific kinematic equations and others questioning the necessary parameters, such as the time the proton is in the machine. There is a mix of attempts to clarify the relationships between the variables involved.

Contextual Notes

Some participants note the need for additional information, such as the time of acceleration, which is not provided in the original problem statement.

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Homework Statement



A proton (mass m = 1.67x10^-27 kg) is being accelerated along a straight line at 2.0x10^15 m/s^2 in a machine. The proton has an initial speed of 2.4x10^7 m/s and travels 2.5 cm.

(a) What is its speed?

(b) What is the increase in its kinetic energy?

The Attempt at a Solution



Is it ok to have no idea where to begin?

I know F=ma, and that V=Vo+1/2at... but I can't see how that helps.

Help me begin?
 
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wadesweatt said:
1. Homework Statement

A proton (mass m = 1.67x10^-27 kg) is being accelerated along a straight line at 2.0x10^15 m/s^2 in a machine. The proton has an initial speed of 2.4x10^7 m/s and travels 2.5 cm.

(a) What is its speed?

(b) What is the increase in its kinetic energy?

3. The Attempt at a Solution

Is it ok to have no idea where to begin?

I know F=ma, and that V=Vo+1/2at^2... but I can't see how that helps.

Help me begin?

You just need two equations.

Kinetic energy.

And an equation that relates Velocity, distance and acceleration.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 
no lowly pion you are wrong what he needs is the other SUVAT equations namely.

S=0.5(u+v)t then rearrange to get V
(u is intitial velocity)

then you put that into the the kenetic energy equation

KE=0.5mv^2

then you have got your anser
 
ffrog said:
no lowly pion you are wrong what he needs is the other SUVAT equations namely.

S=0.5(u+v)t then rearrange to get V
(u is intitial velocity)

then you put that into the the kenetic energy equation

KE=0.5mv^2

then you have got your anser

And what is the time the proton is in the machine?
 
LowlyPion said:
You just need two equations.

Kinetic energy.

And an equation that relates Velocity, distance and acceleration.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2


So, using v^2 = v_0^2 + 2a(Delta x), I can find the final velocity I think. For the delta x part, would it be (2.5 - 0)?

And can I use KE= 1/2mv^2 to find the kinetic energy? If so, wouldn't I use the final velocity found in part a for "v"?

Thanks.
 
wadesweatt said:
So, using v^2 = v_0^2 + 2a(Delta x), I can find the final velocity I think. For the delta x part, would it be (2.5 - 0)?

And can I use KE= 1/2mv^2 to find the kinetic energy? If so, wouldn't I use the final velocity found in part a for "v"?

Thanks.

Yes the V2 = Vi2 + 2ax should do you well.

Part b) is looking for ΔKE. So you are needing to calculate the final KE and subtract the initial.
 
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LowlyPion said:
Yes the V2 = Vi2 + 2ax should do you well.

Part b) is looking for ΔKE. So you are needing to calculate the final KE and subtract the initial.

Ahhhh so I do change in KE=m(v_f)^2 - m(v_i)^2 , right?
 
wadesweatt said:
Ahhhh so I do change in KE=m(v_f)^2 - m(v_i)^2 , right?

Half right anyway.

... i.e don't forget the 1/2.
 
LowlyPion said:
Half right anyway.

... i.e don't forget the 1/2.

haha yes! I knew that I was just typing in a hurry.

Thanks.
 

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