Acceleration and Friction of a Rolling Cylinder

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SUMMARY

The discussion focuses on the dynamics of a thin-walled, hollow cylinder acting as a lawn roller, specifically analyzing its acceleration and friction force when pulled by a constant horizontal force F. The moment of inertia for the hollow cylinder is given by I = MR². The participant correctly identifies that the relationship between linear acceleration (a) and angular acceleration (α) is a = rα due to the no-slip condition. However, confusion arises when substituting the friction force into the equations, leading to an incorrect simplification.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of the relationship between linear and angular quantities
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the equations of motion for rolling objects
  • Learn about the concepts of static and kinetic friction
  • Explore the implications of the no-slip condition in rotational motion
  • Investigate the effects of varying mass and radius on acceleration and friction
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Physics students, educators, and anyone interested in understanding the mechanics of rolling motion and friction in cylindrical objects.

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Homework Statement


A lawn roller in the form of a thin-walled, hollow cylinder with mass M is pulled horizontally with a constant horizontal force F applied by a handle attached to the axle.

a)If it rolls without slipping, find the acceleration.

b)If it rolls without slipping, find the friction force.

Homework Equations


[itex]I_{Hollow Cylinder} = MR^{2}[/itex]

[itex]\sum \tau = f_{friction}R = I\alpha = MR^{2}\alpha[/itex]

[itex]\sum F = F - f_{friction} = F = Ma[/itex]

The Attempt at a Solution


I'm really not sure...it seems like I have too many unknowns (R, a, alpha, friction)
 
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Ok, so I just remembered that because its not slipping, I can change [itex]\alpha[/itex] to [itex]\frac{a}{r}[/itex]

so I get [itex]f_{friction}R = MR^{2}*\frac{a}{R}[/itex]

which cancels down to [itex]f_{friction} = Ma[/itex]

But when I plug that back into the other equation I just get F - ma = ma...

where did I go wrong?
 
Any help, guys?
 

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