Acceleration and magnitude of contact force

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SUMMARY

The discussion focuses on the dynamics of two blocks with masses m1 = 4.00 kg and m2 = 3.00 kg, subjected to a constant force F = 9.00 N on a frictionless surface. According to Newton's 2nd Law, the acceleration of the two-block system is calculated as a = F / (m1 + m2), resulting in an acceleration of 1.5 m/s². The contact force between the two blocks is determined using the formula F_contact = m2 * a, yielding a contact force of 4.50 N.

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  • Understanding of Newton's 2nd Law of Motion
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Joshw17_15
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Two blocks of masses m1 = 4.00 kg and m2 = 3.00 kg are placed in contact with each
other on a frictionless horizontal surface. A constant force F = 9.00 N is applied to the
block of mass m1. a) Determine the magnitude of the acceleration of the two-block
system. b) Determine the magnitude of the contact force between the two blocks.
 
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You haven't put anything in sections 2 or 3 of the template.

Hint for part a) what does Newton's 2nd Law say about the acceleration of the system?
 

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