Acceleration and Tension of two masses on an inclined plane with friction.

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SUMMARY

The forum discussion focuses on calculating the acceleration and tension of two masses on an inclined plane with friction. Mass one is 4 kg and mass two is 5 kg, with a coefficient of friction of 0.24. The correct acceleration is determined to be 2.4 m/s² and the tension in the cord is 37 N, as confirmed by the textbook. The user initially miscalculated the acceleration as 2.86 m/s² and tension as 11.5 N due to neglecting the effects of the hanging mass.

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Imuell1
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Homework Statement


In the attachment there is a drawing of the situation.
Mass one = 4kg and Mass two = 5kg
The coefficient of friction between mass one and the inclined plane = 0.24
Find the magnitude of the acceleration of the masses and the tension in the cord.

Homework Equations


Fk= μkFnormal
Fnetx=Mg*Sinϑ-Fk=Ma
Fnormal=Mg*Cosϑ

Fnetx=Fk+Mg*Sinϑ-T=Ma ?

The Attempt at a Solution



a=(Sinϑ-μkCosϑ)g... a=9.8(Sin30-0.24*Cos30)=2.86m/s2
t=MgSinϑ-MgCosϑ*μk-Ma... t=33.9481-8.1476-14.3=11.5NI'm not sure if the equation I ended up with for acceleration is correct and I am pretty sure that my equation for tension is completely wrong.

The book is giving me the answers a=2.4m/s/s and t=37N
 

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Imuell1 said:
Fnetx=Mg*Sinϑ-Fk=Ma
Fnetx=Fk+Mg*Sinϑ-T=Ma

How can this be?

a=(Sinϑ-μkCosϑ)g... a=9.8(Sin30-0.24*Cos30)=2.86m/s2
t=MgSinϑ-MgCosϑ*μk-Ma... t=33.9481-8.1476-14.3=11.5N

What you're doing here is calculating an acceleration of a system that has a gravity towards sky. And using the acceleration from that to determine the tension of a completely different system.

Hint: Your completely ignoring the hanging mass. You can use it to your advantage.
 
Last edited:
Awesome this helped me a lot. GOD bless you all.
 

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