Acceleration car crash g's experienced?

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SUMMARY

The discussion revolves around calculating the average g-forces experienced by a driver during a car crash, where the car decelerates from 26 m/s to 0 m/s. The initial incorrect assumption was a time duration of 15 seconds, which was later corrected to 0.15 seconds. Using the formula for acceleration, a = (vf - vi) / t, the correct calculation yields an average acceleration of approximately -176.8 m/s², which translates to about 18 g's when divided by the acceleration due to gravity (9.8 m/s²). The final conclusion emphasizes the importance of accurate time measurement in such calculations.

PREREQUISITES
  • Understanding of basic physics concepts, specifically acceleration and deceleration.
  • Familiarity with the formula for acceleration: a = (vf - vi) / t.
  • Knowledge of gravitational acceleration, specifically g = 9.8 m/s².
  • Ability to perform unit conversions and understand the significance of g-forces in physics.
NEXT STEPS
  • Review the concept of acceleration in physics, focusing on the implications of negative acceleration.
  • Learn how to apply the formula a = (vf - vi) / t in various scenarios.
  • Explore the effects of g-forces on the human body during high-speed impacts.
  • Investigate the role of time measurement accuracy in physics calculations.
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Physics students, automotive safety engineers, and anyone interested in understanding the dynamics of car crashes and the effects of acceleration on drivers.

physicsgurl12
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acceleration car crash g's experienced??

Homework Statement



Acceleration is sometimes expressed in multiples of g where g=9.8m/s^2 is the acceleration due to the Earth's gravity. In a car crash the cars velocity may go from 26m/s to 0m/s in 15s. how many g"s are experienced on average by the driver??
a, 23- i know this is wrong
b, 18g
c,22g
d,23g

Homework Equations



we have a, vi, vf and t
so something like v=v0+at

The Attempt at a Solution


v=26m/s+ 9.8m/s^2*15s=173??
 
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The general equation you have is correct, yes. However, look what you know you have. Do you know the final velocity? How about the initial velocity? Does the problem give you the time it takes for the change in velocity?

Also, look at the given problem in your book or on the assignment. The number seems a little off for time. Are you sure it is not 0.15s? 15s would be more like someone stepping on the brakes of a car, rather than an impact.
 


Ignea_unda said:
The general equation you have is correct, yes. However, look what you know you have. Do you know the final velocity? How about the initial velocity? Does the problem give you the time it takes for the change in velocity?

Also, look at the given problem in your book or on the assignment. The number seems a little off for time. Are you sure it is not 0.15s? 15s would be more like someone stepping on the brakes of a car, rather than an impact.

o haha. i guess i typed the time wrong. so that helps a bit but i redid it and got 27.
 


Okay, look at the first half of the hint I gave. Did you rearrange the equation based on what you know? What does it look like when you do that?
 


okay well. I am not really sure what the question is asking me to find.It says g's. i know final and initial velocity and the time it takes to change. but how do i set that up?
 


physicsgurl12 said:

Homework Equations



we have a, vi, vf and t
so something like v=v0+at

Yep. That's the equation you need.
However, you don't have "a" yet.
"a" is what you need to calculate with this formula.

v0 is the same as vi.
And v is the same as vf.

So you have:
vf = vi + a t


physicsgurl12 said:

The Attempt at a Solution


v=26m/s+ 9.8m/s^2*15s=173??

In this formula you substituted g=9.8 for the acceleration.
But that's not right.
"g" is not the acceleration.

And v is not 173 after 15 seconds.
v is vf.

Can you substitute the final velocity vf, and then calculate "a" using your formula?
 


physicsgurl12 said:
okay well. I am not really sure what the question is asking me to find.It says g's. i know final and initial velocity and the time it takes to change. but how do i set that up?

Yes, it says g's.
This means that after you have calculated "a", you need to divide it by "g" to get an answer in g's.
 


okay so then my equation is vf-vi/t=a?? because then you get -17.68 which is pretty close to 18 but its negative.
 


physicsgurl12 said:
okay so then my equation is vf-vi/t=a?? because then you get -17.68 which is pretty close to 18 but its negative.

It is negative because the speed is decreasing to zero.
However, the acceleration acting on the driver is the magnitude of this acceleration and as such positive.

And you should check your numbers.
If I use vi = 26 m/s
and t = 15 s
then I'm getting a = -26 / 15 / 9.8 = -0.1768 g

So you seem to have a couple of decimal points in the wrong place...
 
  • #10


okay but there's no decimal points in the answer choices??
 
  • #11


physicsgurl12 said:
okay but there's no decimal points in the answer choices??

First, are you sure your numbers 26 m/s and 15 s are correct?
You remarked earlier that you made a typo, but you did not clarify.
Is it perhaps .15 s? Which is 0.15 s.

Then, when you write: "b, 18g"
Could that perhaps be: "b ,18g" which is actually "b 0.18g"?
 
  • #12


I like Serena said:
First, are you sure your numbers 26 m/s and 15 s are correct?
You remarked earlier that you made a typo, but you did not clarify.
Is it perhaps .15 s? Which is 0.15 s.

Then, when you write: "b, 18g"
Could that perhaps be: "b ,18g" which is actually "b 0.18g"?

yes it was .15s but there's still no decimals in the answers
 
  • #13


physicsgurl12 said:
yes it was .15s but there's still no decimals in the answers

So redo the calculation with t = 0.15 s?
 

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