Acceleration of a suitcase in an accelerating train after getting pushed

AI Thread Summary
The discussion revolves around calculating the horizontal acceleration of a suitcase in an accelerating train after being pushed. It highlights that Newton's laws do not apply in non-inertial frames, raising questions about the appropriate frame of reference for analysis. The suitcase experiences a force from the push, resulting in an acceleration of 2 m/s² in the Earth frame, while its acceleration relative to the train depends on the train's acceleration. The clarity of the question is criticized, as it does not specify the frame of reference needed for a correct analysis. Ultimately, the suitcase's behavior is independent of the train's motion until it interacts with the train itself.
String theory guy
Messages
26
Reaction score
4
Homework Statement
Statement is below.
Relevant Equations
Newton's second law.
I was doing one of MIT's 8.01.1x course and came across this question.
1670973477837.png

In case 2, how would we be able to theoretically calculate the horizontal acceleration in this non-inertial frame? The course said that Newton's Law do not hold in accelerating frames.

However, could we find the acceleration if we knew the friction force from the train floor on the suit case then sum the forces in the x-direction?
 
Physics news on Phys.org
Friction is ignored in this exercise. You may assume the case is on ideal, frictionless wheels.

In the earth frame (considered not accelerating) the only horizontal force acting on the suitcase is the 10 N from your pushing, so the case accelerates to the tune of 2 m/s2.

With respect to the train the acceleration is a sum. Suppose you push forward and the acceleration ##a## of the train is known (e.g. 1 m/s2, also forward), the acceleration of the suitcase wrt the train is ##2-a## m/s2.

:welcome: ##\qquad## !​

##\ ##
 
  • Love
Likes String theory guy
The question is poorly worded. It is entirely unclear which frame of reference you are supposed to use.
 
  • Like
  • Love
Likes jbriggs444 and String theory guy
The fact that the suitcase is in the train does not imply that the analysis is (or has) to be done in the reference frame of the train. The suitcase is not in a specific frame depending on the train's motion. You can analyze the motion of the suitcase in the ground frame (and use Newton's law) no matter what the train does.

And here, as they say that there are no other forces acting on the suitcase, the suitcase will not even follow the motion of the train when it (the train) accelerates. It can be as well a suitcase on the platform and a train passing by. The train is irrelevant to the suitcase. At least until it hits the end of the car.
 
  • Love
Likes String theory guy
nasu said:
The fact that the suitcase is in the train does not imply that the analysis is (or has) to be done in the reference frame of the train
As I noted, it is unclear which reference frame the question assumes. To get the answer marked correct for case 2, it has to be the train's frame.
 
  • Love
Likes String theory guy
Indeed, the answer make sense with this assumption. But the question should make sense before you know the "right" answer. It is not easy to make good questions, I agree.
 
  • Like
  • Love
Likes String theory guy and jbriggs444
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top