Acceleration of gravity , from a pendulum

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Homework Help Overview

The problem involves determining the acceleration due to gravity on a new planet using a pendulum's swing data. The pendulum has a length of 800 mm, and the explorer observes it completing 24 swings in 1 minute and 20 seconds.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for the period of a pendulum and how to rearrange it to solve for gravity. Questions arise regarding the correctness of the calculations and the units used in the final answer.

Discussion Status

Some participants have provided feedback on the calculations, with one suggesting that the original poster clarify their method and units. There is an ongoing exploration of the assumptions made in the calculations and the interpretation of the results.

Contextual Notes

There is a mention of the use of SI units, and participants are checking the accuracy of the original poster's approach and reasoning without reaching a definitive conclusion.

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Homework Statement



A space explorer lands on a new plant, and he wants to determin the gravity on it. He makes a pendulum with a lengh of 800 mm and he observes it does 24 full swings in 1min and 20 seconds. What is the acceleration of gravity to be from this ?



The Attempt at a Solution



period
=2pie multiplied by square root of (lenth of the pendulum over gravity.

period= 80/24=3.333333. gravity = 2.8

Is this right what i did, any help would be great
 
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Yes, your answer is correct.
 
Well, you are going to have to explain more exactly what you did.

You have determined that [itex]2\pi \sqrt{800/g}= 10/3[/itex]. Now, exactly how did you solve that equation for g? Also, what units is your answer in? I hate to disagree with Hootenanny but your answer makes no sense until you say what the units are.

(That's not true- I love to disagree with Hootenanny!)
 
In light of HoI's post, I'm assuming that your in S.I. units.
 
Last edited:
well i use equation T=2pi sqrt( L/g) =T and T is 10/3, so i solved for g, since i know the Lengh is 801m, then i got it to meters
 

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