Simple pendulum problem - having trouble with the math!!! 1. The problem statement, all variables and given/known data A simple pendulum is set up on Mars where g=3.72m/s^2. How long should pendulum be if period T is to be 2.00 seconds? 2. Relevant equations T=2pia(3.14) times square root of l(length)/gravity 3. The attempt at a solution I placed in 2 seconds for T and divided it by 2pia(3.14). Then I squared this number and then multiplied it by 3.72 to solve for l(length). The correct answer is supposed to be .965 but I did not get this answer. Can anyone please help. I have an exam in 2 days!!!!!!!! Any input will be greatly appreciated.