Acceleration of object in a moving lift

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When a small body is released in a lift moving downwards at constant velocity, its acceleration is observed as "g" downwards by both an observer inside the lift and one stationary relative to the lift shaft. The person inside the lift perceives the object falling normally, while the stationary observer may perceive the fall as slower due to the relative motion of the lift. This creates confusion about the visual experience of the falling object. The discussion highlights the challenges in visualizing the effects of relative motion on perceived acceleration. Overall, both observers agree on the acceleration value, but their perspectives differ based on their frames of reference.
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A small body is released so that it falls to the floor of a lift moving downwards at a constant velocity. How would the acceleration of the body as observed by someone in the lift compared with that observed by a person stationary with respevt to the lift shaft?
 
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acceleration of body as observed by someone in lift is "g" downwards and by someone stationary is also "g" downward
 
i'm having much trouble visualizing what is happening... for the person in the lift, i don't think he would be seeing the ball falling differently as it should be actually falling...
the person outside the lift should perhaps be seeing it falling slower...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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