In the diagram shown below, the lower block is acted on by a force, F, which has a magnitude of 58.6 N. The coefficient of kinetic friction between the lower block and the surface is 0.204. The coefficient of kinetic friction between the lower block and the upper block is also 0.204. What is the acceleration of the lower block, if the mass of the lower block is 4.68 kg and the mass of the upper block is 2.11 kg?
F=ma / friction = [tex]\mu[/tex]mg
The Attempt at a Solution
so i wrote the forces that affect each box
For the upper box ::[tex]\sum[/tex] F= T-[tex]\mu[/tex]m1g
for the lower box :: [tex]\sum[/tex] F= F-T- friction1- friction2
i solved the first equation for tension and then substituted it into the 2nd equation and i solved for acceleration...can u pls. tell me what i'm doin wrong thanx
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