# Acceleration on a curve [kinematics]

## Homework Statement

a car is moving forward at 60 km/h [E 45° N], executes a turn and is now moving at 35 km/h [N 80° W]. If the turn takes 8 seconds to complete the turn what is the average acceleration of the car in m/s?

v2 = v1 + a(t)

## The Attempt at a Solution

v2 = 35
v1 = 60
t = 8
a = ?

v2 = v1+ a(t)

35km/h = 9.72 m/s
60km/h = 16.6 m/s

35 = 60 + a(8)
35-60 = 8a
a= -3.125m/s

i'm not sure if its right, because don't you accelerate positively when you change direction

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LowlyPion
Homework Helper

## Homework Statement

a car is moving forward at 60 km/h [E 45° N], executes a turn and is now moving at 35 km/h [N 80° W]. If the turn takes 8 seconds to complete the turn what is the average acceleration of the car in m/s?

v2 = v1 + a(t)

## The Attempt at a Solution

v2 = 35
v1 = 60
t = 8
a = ?

v2 = v1+ a(t)

35km/h = 9.72 m/s
60km/h = 16.6 m/s

35 = 60 + a(8)
35-60 = 8a
a= -3.125m/s

i'm not sure if its right, because don't you accelerate positively when you change direction
Welcome to PF.

Remember velocity is a vector. As is acceleration. So ... that means that you might do better to resolve the velocities into their components and then figure the change in velocity by x,y to determine the direction and angle of the average change over the 8 seconds.

ok well based on what you said: split into x and y and find average i came up with this diagram:

http://img132.imageshack.us/img132/3949/diagram.jpg [Broken]

I used the previous values (60), (35) to create the x and y for the purple triangle and finally finding the average speed represented by the "?", i then divided that value by the time (8 seconds) and got my answer. Was my method correct?

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LowlyPion
Homework Helper
ok well based on what you said: split into x and y and find average i came up with this diagram:

http://img132.imageshack.us/img132/3949/diagram.jpg [Broken]

I used the previous values (60), (35) to create the x and y for the purple triangle and finally finding the average speed represented by the "?", i then divided that value by the time (8 seconds) and got my answer. Was my method correct?
I prefer to do it algebraically.

Vi = Vix + Viy

Vi = |Vi|*Cosθ x + |Vi|*Sinθ y

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LowlyPion
Homework Helper

You want to keep in mind that

a = ΔV/Δt

where

ΔV = Vf - Vi

alright thank you, solved :D

Hi guys,

I have similar problem with boogaaaa.

As we know, if a car accelerate on curve at certain speed, it will tilt outside the circle track. So i sketch this 2 picture to show how it works.

http://img193.imageshack.us/img193/2323/66057246.jpg [Broken]
http://img194.imageshack.us/img194/9272/96495741.jpg [Broken]

I just wondering, how can the car tilt or flip outside the circle track if the side force (centripetal force) is pointing inside the circle?

My suggestion:
Total Moment about tyre (2); ∑M2=0

So, Fs*h + G*b/2 - FN1*b = 0

I assume that FN1=0 since the car is about to tilt. So here come the problem.

Fs = - G*b / 2h.

The minus sign shows that the side force, Fs, should point outside the circle.

can anyone help me?

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