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Acceleration question -- Deceleration of a baseball being caught by a player

  1. Feb 18, 2015 #1
    1. A baseball is travelling at +18 m/s and is caught by a player. The ball is brought to rest in 0.5 s. What is the acceleration of the ball?


    2. Relevant equations
    Maybe vf=vi+ at ?


    3. The attempt at a solution
    This is under a Horizontal Projectiles worksheet by the way...I'm not sure what to do on this one though. At first I thought to use the equation above and make 18 the final velocity since that's how it's caught...but then what would be the initial? So then I thought...okay maybe the initial could be 18 and the final is 0 since it says 'at rest'. I don't know, this is a bit complicated. Well, If I do it the second way, I get 36 m/s^2
     
    Last edited by a moderator: Feb 19, 2015
  2. jcsd
  3. Feb 18, 2015 #2

    SteamKing

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    When you catch a ball in a glove, how fast is it going when it comes to rest?

    Is the catcher flung backwards by the ball he has caught? :))

    When you are at rest on your couch, do you have any velocity? :wink:

    This problem is complicated only because you are over thinking it.
     
  4. Feb 18, 2015 #3
    so I'm right, it's 36?
     
  5. Feb 18, 2015 #4

    SteamKing

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    It appears to be so.
     
  6. Feb 19, 2015 #5

    haruspex

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    Not quite. The initial speed is carefully stated as "+18m/s". If you plug that in as vi in your "relevant equation" and put vf=0, what exactly do you get for a?
     
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