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Acceleration with change in direction

  1. Sep 29, 2010 #1
    1. The problem statement, all variables and given/known data
    Calculate the average acceleration of the tip of the second hand from the moment it hits the 12 to the moment it hits the 3 position. The radius is 5 cm. Its a clock by the way.
    I've been at it for over an hour and am beggining to susspect my text book is wrong.

    2. Relevant equations
    a= v2 - v1 / t

    3. The attempt at a solution
    I got 0.0047 m/s squard.
    The text book says its 4.9 x 10 to the power of negative four [S 45 W]. So 0.00049 m/s squard.
  2. jcsd
  3. Sep 29, 2010 #2
    Can you give the detailed explanation?.....by the way did you do the conversion right i.e. 5cm=0.05m
  4. Sep 30, 2010 #3
    i solved it and found the text is right .... you havent done the conversion.
    5cm = 0.05m
  5. Sep 30, 2010 #4
    Yes the answer is correct as per the textbook!
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