Action reaction problem or Newton's 3 law

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Homework Help Overview

The discussion revolves around a problem involving two blocks, A and B, where block A is on top of block B, and both are on a surface with friction. The original poster attempts to identify all the forces acting on block B while considering Newton's third law of motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the forces acting on block B, including normal forces, gravitational force, and frictional forces. There is a focus on understanding the action/reaction pairs as described by Newton's third law. Some participants question the nature of the friction forces and their roles in the system.

Discussion Status

The discussion is ongoing, with participants providing hints and clarifications about the forces involved. There is an exploration of the implications of friction forces and their relationship to the motion of block B. Multiple interpretations of the forces are being examined, and some participants express uncertainty about the complete identification of forces.

Contextual Notes

Participants are working under the assumption that block B is stationary, which influences their analysis of the forces acting on it. The discussion also highlights the need for clear definitions of the surfaces involved, as there is some confusion regarding the terminology used to describe the surface beneath block B.

astrololo
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Homework Statement



There is a bloc B that is on a surface S. A bloc A is on on the bloc B. We pull the rope towards the right. There is friction between all surfaces and the blocs stay stationary (They don't move). Identify all the forces which are applied on the bloc B.
http://imgur.com/Hzgc8pP

Homework Equations



No equations.

The Attempt at a Solution



I know that there is going to be a Normal upward, another normal that is downward because it is a reaction according to Newton's third law, the gravitational force downward. I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A. Now, I don't know what else to find... There is one missing...

Here is another image http://imgur.com/FYWfLgE[/B]
 
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Consider any pair of Newton's Third Law action/reaction forces. The two forces never act on the same object.

So, for example, Block A pushes down on Block B, and Block B pushes up on Block A.
 
Mister T said:
Consider any pair of Newton's Third Law action/reaction forces. The two forces never act on the same object.

So, for example, Block A pushes down on Block B, and Block B pushes up on Block A.
Yes but I don't see what else I can get... I'm only interested in object B and I got one pair of normal forces on the bloc A and B.
 
Draw a diagram showing only Block B. On the diagram indicate only the forces that are acting on Block B.
 
Mister T said:
Draw a diagram showing only Block B. On the diagram indicate only the forces that are acting on Block B.
I know that there is going to be a Normal upward, another normal that is downward because it is a reaction according to Newton's third law, the gravitational force downward. I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A.http://imgur.com/T9RXe3F
 
astrololo said:
I know that there is going to be a Normal upward,

Exerted by the table.

another normal that is downward

Exerted by Block A

because it is a reaction according to Newton's third law,

(Every force is a reaction according to Newton's Third Law!)

the gravitational force downward.

Exerted by Earth.

I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A.

Exerted by Block A.

And one more ...

Hint: The net force on Block B must be zero because Block B is not in motion.
 
Mister T said:
Exerted by the table.
Exerted by Block A
(Every force is a reaction according to Newton's Third Law!)
Exerted by Earth.
Exerted by Block A.

And one more ...

Hint: The net force on Block B must be zero because Block B is not in motion.
Oh, there's a friction force to the left because if there wasn't one, then the block B would be moving, right ? So it's not a reaction but more of a "stabilizer", right ?

Also, when I said "I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A." and you said : "Exerted by Block A." You mean that the block A is responsible for this reaction to the right, right ?
 
astrololo said:
Oh, there's a friction force to the left because if there wasn't one, then the block B would be moving, right ? So it's not a reaction but more of a "stabilizer", right ?

Table pushes to the left on Block B, Block B pushes to the right on Table. It's an action/reaction pair. We call it friction.

Also, when I said "I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A." and you said : "Exerted by Block A." You mean that the block A is responsible for this reaction to the right, right ?

Correct!

Block A pushes to the right on Block B, Block B pushes to the left on Block A. It's an action/reaction pair. We call it friction.
 
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Mister T said:
Table pushes to the left on Block B, Block B pushes to the right on Table. It's an action/reaction pair. We call it friction.
Correct!

Block A pushes to the right on Block B, Block B pushes to the left on Block A. It's an action/reaction pair. We call it friction.
Just one thing, the "S" isn't a table but a floor.

Forget it I understood what you meant Thanyou!
 

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