Why Do Three Blocks on a Frictionless Surface Accelerate at the Same Rate?

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SUMMARY

The discussion centers on the physics problem involving three blocks (A=0.4 kg, B=0.1 kg, C=0.3 kg) on a frictionless surface subjected to a horizontal force of 2.4 N applied to block A. The conclusion drawn is that all three blocks accelerate at the same rate due to the absence of friction, which prevents any relative motion between them. The acceleration can be calculated using Newton's second law, confirming that blocks B and C cannot accelerate slower than block A, as there are no forces acting to differentiate their motion.

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Homework Statement



On a surface without friction, we have 3 blocs with mass A=0,4 kg B=0,1 Kg C=0,3 Kg which are placed one beside the other, with A being first, B second and C third.. If we push on the bloc A with a horizontal force of 2,4 N, determine what is the acceleration and what are the forces of the normals which are located between the blocs.

http://imgur.com/F9PQwKK

Homework Equations



Sum force of x = m * a(x)

The Attempt at a Solution


I was able to resolve the problem and got the right answers. What I was wondering is why should I assume that the acceleration is going to be the same for the 3 blocs ? I was able to solve the problem because I assumed this to be true, but I don't know why it is. I guess that the fact there's no friction makes this true. any help ?
 
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Well, given the picture, B and C can't accelerate slower than A. There also is nothing that could make them accelerate faster.

Does that answer your question ?
 
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BvU said:
Well, given the picture, B and C can't accelerate slower than A. There also is nothing that could make them accelerate faster.

Does that answer your question ?
Said this way, it makes sense. Ty
 

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