Activity - Equilibrium Expressions

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The discussion centers on the equilibrium constant expressions, Kc and Kp, and their relationship to activity. It highlights that while K is typically reported without units due to cancellation in the equilibrium constant expression, Kc and Kp are not equal due to differing reference states—1 atm (or 1 bar) for pressure and 1 mol/L for concentration. An exception arises when the sum of the powers in the equilibrium expression's numerator and denominator is the same, leading to Kc equaling Kp despite the different reference states. The conversation further explores the impact of changing the reference pressure, noting that if the reference pressure is altered (e.g., from 1 bar to 0.5 bar), the equilibrium expression for Kp changes by a factor of 2Δn, but if Δn equals 0, K remains unaffected by the reference pressure.
i_love_science
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When I use the concept of activity to express the equilibrium constant expression, for either equilibrium pressures or concentrations, the units cancel and the value of K has no units (which is how K is customarily reported). But because of the difference in reference states (the reference pressure is 1 atm (or 1 bar) and the reference concentration is 1 mol/L), Kc is not equal to Kp.

Why is there an exception to this principle when the sum of the powers in the numerator and the denominator of the equilibrium expression are the same? Aren't the reference states still different? In this case Kc is equal to Kp. Thank you!
 
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Consider changing the reference pressure, say from 1 bar to 0.5 bar. Each reagent pressure (expressed as a multiple of the reference pressure) will increase by a factor of 2. The expression for Kp will therefore change by a factor 2Δn. If Δn = 0, the value of K is independent of the reference pressure.
 
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Likes etotheipi, i_love_science and jim mcnamara
Thanks, I understand now.
 
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