- #1

- 3

- 0

## Homework Statement

An insulated beaker with negligible mass contains liquid water with a mass of 0.275kg and a temperature of 77.7.

How much ice at a temperature of -17.4 must be dropped into the water so that the final temperature of the system will be 29.0?

Take the specific heat of liquid water to be 4190 , the specific heat of ice to be 2100 , and the heat of fusion for water to be 334 x 10^3 .

## Homework Equations

Q = mc[tex]\Delta[/tex]T

Q_tot = q_1 + q_2 ..etc

Fusion - Phase change

## The Attempt at a Solution

I am almost certain I have done this correctly, but masteringphysics will not admit it! :/

I will leave off some units as I have made sure they all match up.

q1: Ice to 0C

q2: Ice fusion mw= mass water

q3: Ice to 29C mi = mass ice

q4: H20 to 29C

((mw)(4190)(29C-77.7C) + (mi)(2100)(0C+17.4C)+(mi)(334 X 10^3)+(mi)(4190)(29C-0C))= 0

I solve for mi and get 0.114kg ice. MP no likey. Anyone care to check this?

Thanks in advance,

Magicarp