Adding Scalar Multiples of Vectors Graphically

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    Scalar Vectors
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Homework Help Overview

The discussion revolves around graphically adding scalar multiples of vectors, specifically calculating the vector C = 1.5A - 3B, where A and B are given magnitudes. The original poster expresses difficulty in understanding the graphical representation of this vector addition.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the head-to-tail method for vector addition and suggest scaling the vectors A and B appropriately. There are questions about the correctness of the graphical representation and the identification of the resultant vector.

Discussion Status

Some participants provide guidance on how to construct the vectors graphically, while others express uncertainty about the steps involved. There is an ongoing exploration of the correct representation of the resultant vector, with no clear consensus reached on the final answer.

Contextual Notes

The original poster mentions having limited attempts left to solve the problem, indicating a constraint on the number of submissions allowed. There is also a reference to confusion regarding the angles of the vectors involved.

Turtlie
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Homework Statement


Draw the vector C = 1.5A -3B
(Mastering Physics problem)
A is 4.5 and B is 1.0

The Attempt at a Solution


I've tried it 4 times and still can't do it. I've looked at some sites but I guess I just don't understand it. I've heard of the head to tail method, or something similar, but I either did it wrong or didn't understand it.

I got the first one right, but I've never done any with the different-angled vectors (aside from East/West, North/East)

Oops, picture would be helpful.
2jsbvm.jpg
 
Last edited:
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Make A 1.5 times as long.
Make B 3 times as long and in the opposite direction to form -3B.
Copy the extended -3B so that it begins at the end of 1.5A. The total is the new vector going from the beginning of 1.5A to the end of the relocated -3B. Looks like about 9 to the right and 3 up.
 
Delphi51 said:
1. Make A 1.5 times as long.
2. Make B 3 times as long and in the opposite direction to form -3B.
3. Copy the extended -3B so that it begins at the end of 1.5A.
4. The total is the new vector going from the beginning of 1.5A to the end of the relocated -3B. Looks like about 9 to the right and 3 up.

2lm2cxy.jpg


Is that right? Not completely sure about four though :confused:
 
Looks good! Ignore 4. Count your answer from the beginning of 1 to the tip of 3. It is 9 squares to the right and 4 squares up. Often written as (4,3).
 
Wait so which arrow would be the answer? The one that I labeled as 3?

Edit: Well 3 isn't the answer. I tried that one so now I have like 1 try left.
 
Last edited:

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