A plane, travelling with a velocity relative to the air of 320km/h [28 S of W], passes over Winnipeg. The wind velocity is 72km/h . Determine the displacement of the plane from Winnipeg 2.0 h later. Cosine Law -> c^2 = b^2 + a^2 - 2*b*a*Cos<C Sine Law- (Sin<A)/a = (Sin<B)/b = (Sin<C)/c Addition and Subtraction of Vectors West is left, South is down. 1. Drew the thing. It was pretty. 2. Drew a line parallel to West and found part of the really big angle. Then I added 90 to it. = 118 degrees 3. Used Cosine law to get resultant Velocity 4. Used Sine law to get the top little angle. Added it to the existing 28 degrees to get my resultant angle S of W 5. Burst into tears because the answer in the book brutally murdered my already low self-esteem.