Calculating Net Force & Acceleration: Addition of Forces Explained

  • Thread starter Thread starter Benjamin_harsh
  • Start date Start date
  • Tags Tags
    Addition Forces
Click For Summary

Homework Help Overview

The discussion revolves around the concepts of net force and acceleration, specifically examining the relationship expressed in the equation ##\sum F_{X} = m.a##. Participants are exploring the implications of Newton's second law in scenarios involving multiple forces acting on an object.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the equivalence of ##\sum F_{X}## and ##m.a##, with some expressing confusion over the terminology and application of these concepts. There is a focus on understanding how net forces are calculated when multiple forces are present.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the definitions and applications of net force and acceleration. Some guidance has been provided regarding the relationship between individual forces and net force, but there is no explicit consensus on the understanding of the terms used.

Contextual Notes

Participants are grappling with the distinction between single and multiple forces acting on an object, and how this affects the application of Newton's second law. There is mention of specific forces such as friction and normal force, which are relevant to the problem context.

Benjamin_harsh
Messages
211
Reaction score
5
Homework Statement
A horizontal force of 150N is applied on a 20kg box which causes it to move to the right. What is the acceleration if the coefficient of kinetic friction is 0.25?
Relevant Equations
##\sum F_{X} = F - F_k##, ##ma = F - \mu_{k}.F_k##
244257

##\sum F_{X} = F - F_k##

(The net force, ##\sum F_{X}## is always equal to m.a)

##ma = F - \mu_{k}.F_n##

##ma = F - \mu_{k}.(mg)## [Here ##F_n = mg## when body is on flat surface]

##20(a) = 150 - 0.25(20)(10)##

##\large a = \frac {150 - 0.25(20)(10)}{20}##

##\large a = 5\frac{m}{sec^2}##

How ##\sum F_{X} = m.a## ?
 
Last edited:
Physics news on Phys.org
Is there a question?
 
PeroK said:
Is there a question?

My question: How ##\sum F_{X} = m.a##?

Someone edited my title of the post.
 
Benjamin_harsh said:
My question: How ##\sum F_{X} = m.a##?

Someone edited my title of the post.

How not?
 
PeroK said:
How not?

I know ##F = M.A##. I never heard ##\sum F_{X} = m.a##.
Please explain.
 
Benjamin_harsh said:
I know ##F = M.A##. I never heard ##\sum F_{X} = m.a##.
Please explain.

You did all this in your OP. You can look at Newton's second law two ways.

If you assume that ##F## is the only force on an object, then you have simply ##F = ma##.

But, if an object has more than one force on it (in your example there are 4 forces on the object), then the acceleration is related to the sum of the forces:

##\sum F = ma##

Sometimes, to emphasise this, we talk about the net force:

##F_{net} = \sum F = ma##
 
Benjamin_harsh said:
I know ##F = M.A##. I never heard ##\sum F_{X} = m.a##.
Please explain.
In the first formula above, F represents the net force acting on an object, which is either the force if there is only a single force, or the sum of forces, if there are more than one force.

In your drawing, the net vertical force is zero; the upward normal force is balanced by the gravitational force. These two forces are equal in magnitude, but opposite in sign, so the block doesn't fly up or sink into the surface. In the horizontal direction, if the force acting to the right is larger in magnitude than the friction force (which acts toward the left), the horizontal forces aren't balanced, and the block will accelerate to the right.
 
  • Like
Likes   Reactions: PeroK

Similar threads

Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
11
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 97 ·
4
Replies
97
Views
6K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 21 ·
Replies
21
Views
2K