Age of rocks calculation - I only need little help

Click For Summary
SUMMARY

The discussion centers on calculating the number of half-lives that have passed since a rock's formation based on the ratio of lead-207 to uranium-235 isotopes. The user identifies that the ratio is 1:31 and seeks guidance on converting this ratio into actual atom counts for calculations. The correct interpretation reveals that 5 half-lives have elapsed, as confirmed by the calculations presented. The formula used to determine the number of un-decayed isotopes is N(t) = N(0) (1/2)^(t/halflife), where N(0) represents the initial quantity of uranium-235.

PREREQUISITES
  • Understanding of radioactive decay and half-lives
  • Familiarity with isotopes, specifically lead-207 and uranium-235
  • Basic algebra for manipulating equations
  • Knowledge of the formula N(t) = N(0) (1/2)^(t/halflife)
NEXT STEPS
  • Study radioactive decay principles in detail
  • Learn how to apply half-life calculations in geological contexts
  • Explore isotopic dating methods used in geology
  • Investigate the significance of parent-daughter isotope ratios
USEFUL FOR

Students studying geology, physics enthusiasts, and anyone interested in understanding radioactive dating techniques and calculations.

wannie112
Messages
4
Reaction score
0
How many half lives have passed since a particular rock was formed if a sample of the rock contains 31 times as much lead-207 than uranium-235?
I know that I need to do a table and calculate
I know how to do this question but the thing I need help on is how do I know the number of atoms in order to do a table and calculate. Like I have the ratio of parents:daughter isotope which is 1:31 right? but how do I do this? Just tell me how and I will do it myself. Actually I don't know physics, I'm studying it all by myself and I got this question from my friend's homework and I'm stuck on it, there are 3 questions like it and I need help on how to turn this ratio into actual numbers in order to calculate how many half lives have passed. If I don't need to turn it into numbers then please tell me how do I solve this question? Thank you :)

EDIT: okay so that's what I did is this correct?

1 - 31 half lives=5
2 - 30 half lives=4
4 - 28 half lives=3
8 - 24 half lives=2
16 - 16 half lives=1
32 - 0 half lives=0
so 5 half lives have passed
Correct??
 
Last edited:
Physics news on Phys.org
5 half lives is correct.

ehild
 
Last edited:
Hmm? You didn't really explain anything...how did you get to 32? I got to 5.
 
I meant 5, sorry... As the original amount decreased to 1/32-th.

hild
 
oo thank you :)..and my way is correct do I have to do any formulas?
Thank you very much ^^
 
The daughter atoms present + number of un-decayed U235 atoms=N(0):
31N + N =N(0)

The number of un-decayed isotopes present at time t is

N(t)=N(0) (1/2)t/halflife,

where N(0) is the number initially.

N=N(0)/32, 32 =25, ...
ehild
 
I see :D Now I understand everything, thank you!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
Replies
7
Views
6K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K