Age of Seashell: Calculating 14-C Half Life

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SUMMARY

The discussion focuses on calculating the age of a seashell using Carbon-14 dating, specifically determining the time it takes for 14-C to decay to 90% and 99% of its initial value. The half-life of 14-C is established as 5570 years, leading to a decay constant (k) of 1.24 x 10^-4. The calculations yield an age of 847 years for the seashell at 90% decay and approximately 81.1 years for the 99% decay. Participants emphasize the importance of maintaining high precision in calculations, particularly for exponential decay functions.

PREREQUISITES
  • Understanding of Carbon-14 dating principles
  • Familiarity with exponential decay equations
  • Knowledge of half-life calculations
  • Basic proficiency in using scientific calculators or graphing software
NEXT STEPS
  • Explore advanced Carbon-14 dating techniques and their applications
  • Learn about the mathematical derivation of decay constants
  • Investigate the impact of precision in exponential calculations
  • Graph exponential decay functions using software like Desmos or GeoGebra
USEFUL FOR

Students in chemistry or environmental science, educators teaching radiometric dating, and professionals involved in archaeological dating methods will benefit from this discussion.

matt222
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Homework Statement



seashell HAVE 90% of 14-C as a livining shell of the same size half life is 5570 years, how old is it in years

how many yrs did it take for 14-C to diminish from its initial value to 99% of that?

Homework Equations





The Attempt at a Solution



for the first part of problem 90% N0=N0exp(-kt), where k is decay constant from this k=1.24x10^-4
so t=847 years

for the second part of the problem we have the same decay constant k, so 99%N0=N0exp(-kt)

so for t I got t=81.1years

I think the first part is ok but i am not sure i about the second one
 
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Looks good to me. Is your 3 digit accuracy for k sufficient? If I were you, I would keep about 5 digit accuracy because exponent accuracy strongly affects the accuracy of the power.
 
but it confused me the second part I am not sure about it 81 years compared to 847 years
 
I get 80.8 rather than 81.1, keeping all the digits on my calculator until rounding the final answer. You don't say what you are confused about. If you mean losing 1% in one tenth the time it loses 10%, that seems almost too reasonable to be true. Normally you can't trust your intuition on non-linear functions. It might be worth graphing the decay function on your calculator or computer to see if the function is fairly linear in that range.
 

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