Airplane's motion relative to the ground involving wind speed

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SUMMARY

The discussion centers on calculating an airplane's ground speed and position relative to wind conditions. The plane, flying east at 500 mph, encounters a southward wind of 50 mph. The equations used to determine the plane's velocity relative to the ground (PG) are established as (V_x)_PG = (V_x)PW + (V_x)WG and (V_y)_PG = (V_y)PW + (V_y)WG. The confusion arises in correctly applying the wind's effect on the plane's trajectory, particularly in the y-component of the velocity.

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sp3sp2sp
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Homework Statement


Plane is 300miles E of chicago and it leaves flying east at 500mph. Wind is blowing 50mph south.
What is planes ground speed?
Where is plane 0.6 hours later when pilot expects to land in cleveland?

Homework Equations

The Attempt at a Solution


This is how I set it up
I want PG, which is plane speed relative to ground
W = wind, P = plane, G = ground

(V_x)_PG = (V_x)PW + (V_x)WG
(V_y)_PG = (V_y)PW + (V_y)WG

So now I am filling in the values and it doenst look right, so I wanted to check this preliminary step

(V_x)_PG = (V_x)PW + (V_x)WG --> 500mph = (V_x)PW + 0mph
(V_y)_PG = (V_y)PW + (V_y)WG --> 0mph = (V_y)PW + (-50mph)

I think (V_x)PW should also be 500mph and (V_y)PW should = +50mph to make the equations correct, but the 2 equations are not telling me anything I didnt already know from the question stem.

Is this correct so far?
thanks for any help
 
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sp3sp2sp said:
(V_y)_PG = (V_y)PW + (V_y)WG --> 0mph = (V_y)PW + (-50mph)
I would take "flying east" as referring to the heading, i.e. direction relative to the wind.
 
OK thanks..but y-component of plane's speed relative to the wind, (V_y)_PW would be 0 wouldn't it? Because it travels east there is no movement in y direction, so equation for y should be
(V_y)_PG = (V_y)PW + (V_y)WG
0mph = +50mph + - 50mph

I was hoping to get opinion if I've even set up equation correct because that's what I think a lot of the problem is about.
thanks
 
sp3sp2sp said:
(V_y)_PW would be 0
Yes, so why have you again written
sp3sp2sp said:
(V_y)_PG = (V_y)PW + (V_y)WG
0mph = +50mph + - 50mph
?
 
Can someone please walk me through this problem? I am getting more and more confused every time I try to work the problem. Thanks in advance
 
sp3sp2sp said:
Can someone please walk me through this problem? I am getting more and more confused every time I try to work the problem. Thanks in advance
Fill in the values in your equation
sp3sp2sp said:
(V_y)_PG = (V_y)PW + (V_y)WG
using your new understanding that Vy,PG is unknown and
sp3sp2sp said:
, (V_y)_PW would be 0
 

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