I havent done Maths for some time, and my Algebra needs some work. 1. The problem statement, all variables and given/known data Two questions in particular; 1. The problem statement, all variables and given/known data Two questions in particular; a) Rearrange for x in terms of y and t, to its simplest form. t(t-x) = 3y(3y-x) [3y-t =/= 0] b) Solve for x (x+4)/x - 14/(2x-1) = 0 2. Relevant equations 3. The attempt at a solution a) I have taken a couple of different approaches, but here is one t^2 - tx = 9y^2 - 3yx 3yx = 9y^2 - t^2 + tx x = (9y^2 - t^2 + tx) / 3y x = 3y - t^2 + tx tx = t^2 + x - 3y x = t + x/t - 3y/t x - x/t = t - 3y/t And when i try to take it any farther i end up going round in circles, or finding fanciful methods of ending up where i started. b) Multiplying both Numerators by (x) and (2x-1), and cancelling, leaves (x+4)(2x-1)=14x 2x^2 - x +8x - 4 = 14x 2x^2 - 7x = 4 x (2x-7) = 4 x = 4/(2x-7) 4/x - 2x = -7 Similarly, i cant see how to go any farther without going round in circles. Can i go to 2x^-1 - x = 7/2? Even then i wouldnt know where to go. Thanks to anyone who offers help.