I havent done Maths for some time, and my Algebra needs some work.(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

Two questions in particular;

1. The problem statement, all variables and given/known data

Two questions in particular;

a) Rearrange for x in terms of y and t, to its simplest form.

t(t-x) = 3y(3y-x) [3y-t =/= 0]

b) Solve for x

(x+4)/x - 14/(2x-1) = 0

2. Relevant equations

3. The attempt at a solution

a) I have taken a couple of different approaches, but here is one

t^2 - tx = 9y^2 - 3yx

3yx = 9y^2 - t^2 + tx

x = (9y^2 - t^2 + tx) / 3y

x = 3y - t^2 + tx

tx = t^2 + x - 3y

x = t + x/t - 3y/t

x - x/t = t - 3y/t

And when i try to take it any farther i end up going round in circles, or finding fanciful methods of ending up where i started.

b) Multiplying both Numerators by (x) and (2x-1), and cancelling, leaves

(x+4)(2x-1)=14x

2x^2 - x +8x - 4 = 14x

2x^2 - 7x = 4

x (2x-7) = 4

x = 4/(2x-7)

4/x - 2x = -7

Similarly, i cant see how to go any farther without going round in circles. Can i go to 2x^-1 - x = 7/2? Even then i wouldnt know where to go.

Thanks to anyone who offers help.

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# Homework Help: Algebra (easy for you, difficult for me)

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