Alternating series convergence

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SUMMARY

The discussion focuses on determining the convergence range of two McLaurin series: ln(1+x) and ln(1-x). The first series converges for -1 < x ≤ 1, while the second series converges for -1 < x < 1. The alternating series test is employed to analyze convergence, and the radius of convergence is identified as a key factor in establishing the valid x values for both series.

PREREQUISITES
  • Understanding of McLaurin series and their expansions
  • Familiarity with the alternating series test
  • Knowledge of power series and radius of convergence
  • Basic calculus concepts related to series convergence
NEXT STEPS
  • Study the application of the alternating series test in detail
  • Learn how to derive the radius of convergence for power series
  • Explore sigma notation for representing series
  • Investigate the properties of logarithmic functions and their series expansions
USEFUL FOR

Students and educators in calculus, mathematicians analyzing series convergence, and anyone studying power series and their applications in mathematical analysis.

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Homework Statement


I have 2 McLaurin series.

1) ln(1+x) = x - (x^2)/2 + (x^3)/3 - (x^4)/4 + ...

2) ln (1-x) = -x - (x^2)/2 - (x^3)/3 - (x^4)/4 + ...

The Attempt at a Solution



I want to find the range of x values for which series 1) and 2) converge.

For 1) I am using the alternating series test. I know how to test for convergence, but how do I find the range of x values for which it converges?

Am I missing something very obvious?
 
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Try to write the expansions of ln(x+1) and ln(1-x) in sigma notation, and then i believe all you need to do is find the radius of convergence of that power series, and it will give you all the values of x for which the two series converge.
 

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