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## Homework Statement

An alternating source drives a series RLC circuit with an emf amplitude of 6.00 V, at a phase angle of +30.0 degrees. When the potential difference across the capacitor reaches its maximum positive value of +5.00 V, what is the potential difference across the inductor (sign included)?

## Homework Equations

I know for series RLC circuits the following equations are relevant

[tex]I= \frac{E_m}{ \sqrt{R^2+(\omega_dL-1/\omega_dC)^2}}[/tex]

[tex]\tan{\phi}=\frac{X_L-X_C}{R}[/tex]

**The "E" used in the above equation is supposed to be the symbol for emf**

## The Attempt at a Solution

It seems to me that there isn't enough information to make use of the above equations since there are too many unknowns. We don't know what the driving angular frequency is for one and to calculate R we need to know I etc. I believe that there is something I've missed or am not aware of. Perhaps there's a connection somewhere I'm not making.

Please point me in the right direction.

Thanks!

phyz