Alternative method to the matrix problem?

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The discussion revolves around solving the matrix equation X² + 3X + 2I = 0 for matrices of the form [x 0; y z]. One participant suggests deriving the minimal polynomial from the equation, noting that it divides t² + 3t + 2. There is a mention of eigenvalues and the fact that for triangular matrices, eigenvalues appear on the diagonal, which could help in identifying x and z. However, the complexity of finding y leads to the conclusion that the original method of equating entries may still be necessary. Ultimately, the conversation highlights the interplay between matrix theory concepts like minimal polynomials and eigenvalues in solving such problems.
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Homework Statement


Find all real matrices,X, of the form

[x 0]
[y z]

such that X2+3X+2I=0

(I is the identity matrix)


Homework Equations





The Attempt at a Solution



The only method I know is to work out X2 and then 3X, add to 2I, then equate the corresponding entries with the zero matrix. Have 3 equations with three unknowns and solve. But is there any other method in which I can use to shorten the amount of writing I will have to do?
 
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If X^2+3X+2I=0, then the minimal polynomial of X divides t^2+3t+2=(t+1)(t+2), and take it from here.
 
morphism said:
If X^2+3X+2I=0, then the minimal polynomial of X divides t^2+3t+2=(t+1)(t+2), and take it from here.

I was thinking to do something like that, but the identity matrix in it confused me.
Now I should re-write the equation as

X^2++X+2I^2=(X+I)(X+2I)=0 and go from here right?
 
Well, it depends on what you mean by "go from here"! If you're going to say something like "Then X=-I or X=-2I", then you'll be off the mark. Do you know what a minimal polynomial is?
 
morphism said:
Well, it depends on what you mean by "go from here"! If you're going to say something like "Then X=-I or X=-2I", then you'll be off the mark. Do you know what a minimal polynomial is?

Yes, that is what I thought to do... No idea what a minimal polynomial is.
 
OK, do you know what eigenvalues are, then?

By the way, for matrices, AB=0 doesn't imply that A=0 or B=0. Try to come up with an example of this - and make sure you understand why this happens. In fact, you can have a nonzero matrix A such that A^2=0.
 
morphism said:
OK, do you know what eigenvalues are, then?

By the way, for matrices, AB=0 doesn't imply that A=0 or B=0. Try to come up with an example of this - and make sure you understand why this happens. In fact, you can have a nonzero matrix A such that A^2=0.

Yes,I know what eigenvalues are, and the characteristic polynomial. I am aware the AB=0 doesn't always mean that A=0 or b=0...I always forget this in matrices.
 
Then I guess a shortcut would be to notice that the eigenvalues of a triangular matrix will lie on its diagonal. And because X^2+3X+2I=0, the eigenvalues of X will satisfy the equation t^2+3t+2=0. So this'll give us why x and z will be. To find y you'll just have to do it the long way.

Well come to think of it, this isn't really a shortcut at all.
 
I guess I will have to stick with my initial method.
My math course, doesn't include the topic of e.vectors/values but since I did Further math I just happen to know it.
 

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