Am I doing this right? - rotational motion

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SUMMARY

The discussion centers on calculating the distance a wheel rolls uphill before stopping, given its parameters: a radius of 1.23 m, mass of 7.7 kg, and a moment of inertia defined as I = 1/2 MR^2 for a solid disk. The wheel starts with an angular speed of 16.1 rad/s and rolls uphill at a 30-degree angle until it stops due to gravitational forces. The correct approach involves using the energy conservation equation 1/2 Iω² + 1/2 mv² = mgh, substituting v with Rω, and applying trigonometry to find the hypotenuse for the distance traveled.

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Hint: Consider the wheel's energy.
Consider a wheel of radius 1.23 m, mass
7.7 kg and moment of inertia I =1/2 MR^2
(it's a solid disk). The wheel rolls without
slipping in a straight line in an uphill direction 30 degrees above the horizontal. The wheel starts at angular speed 16.1 rad/s but the ro-
tation slows down as the wheel rolls uphill,
and eventually the wheel comes to a stop and
rolls back downhill.
The acceleration of gravity is 9.8 m/s^2
How far does the wheel roll in the uphill
direction before it stops? Answer in units of
m.

This is what I plan to do:

1. Use:

1/2 Iw^2 +1/2 mv^2 = mgh

by substituting Rw for v and solving for h.

2. "h" would equal the "y" component so I would then go on to use trig. to find the hypontenuse.

Would that work?
 
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yes, it is correct
 
Thanks for the confirmation. I don't think I'm good at canceling variables out as I got the wrong answer the first time (tried to cancel out the masses). But the second time around I just plugged in everything and it came out to a different and correct answer. :)
 

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