Undergrad Am I using the right limits on this triple integral?

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SUMMARY

The discussion centers on the evaluation of a triple integral involving a change of variables from (r, s, t) to (θ, a, p). The Jacobian for this transformation is established as J = (a * p * sin(θ)) / r. The proposed limits for the integration, specifically from 0 to π for θ, are confirmed as correct based on geometric interpretations of the triangle formed by the sides r, a, and p. This conclusion validates the friend's assertion regarding the limits of integration.

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oliverkahn
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Let:

\begin{align}
r&=\sqrt{a^2 + p^2 - 2ap \cos \theta}\\
s&=a\\
t&=p\\
f(r) &= \text{continuous function of } r\\
g(s) &= \text{continuous function of } s\\
\end{align}

Consider the expression:

\begin{align}
\int_{q'}^q \int_{b'}^b g(s)\ \int_{s-t}^{s+t} f(r)\ dr\ ds\ dt\
\end{align}

We next have to change the variables from ##(r,s,t)## to ##(\theta, a, p)##. The Jacobian of the coordinate transformation (after computing) is:

##J= \dfrac{\partial r}{\partial \theta}=\dfrac{a\ p\ \sin\theta}{r}##

Thus our new function becomes ##J\ f(r) =\dfrac{a\ p\ \sin\theta}{r} f(r)##

Question:

One of my friends said that the limits of the integration would be as follows:

\begin{align}
\int_{q'}^q \int_{b'}^b g(a)\ \int_{0}^{\pi} \dfrac{a\ p\ \sin\theta}{r} f(r) \ d \theta\ da\ dp\
\end{align}

Is he correct?
 
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If you look at it geometrically, r, a, p are lengths of three sides of a triangle, with r opposite ##\theta##. The limits on r are for the two other sides subtracting or adding, which is equivalent to ##\theta## being 0 or ##\pi##. Your friend is correct.
 
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