Ammeters & Frequency: Understanding the Relationship

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SUMMARY

The discussion centers on the behavior of ammeters when measuring alternating current (A.C.) at varying frequencies. It establishes that as frequency increases, the inductive reactance (X_L = ωL) of the circuit components increases, leading to a higher impedance across the parallel resistor. Consequently, more current bypasses the shunt resistor and flows through the moving coil of the ammeter, potentially resulting in clipping. The conversation also highlights the importance of considering the resistance of the moving coil, which affects the overall impedance at higher frequencies.

PREREQUISITES
  • Understanding of A.C. circuit theory
  • Familiarity with inductive and capacitive reactance
  • Knowledge of ammeter operation and design
  • Basic principles of impedance and current division
NEXT STEPS
  • Research the effects of frequency on inductive reactance in A.C. circuits
  • Study the design and limitations of moving coil ammeters
  • Explore methods to mitigate clipping in ammeter readings
  • Learn about impedance matching techniques in A.C. measurements
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Electrical engineers, physics students, and technicians involved in A.C. circuit design and measurement, particularly those working with ammeters and frequency analysis.

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Homework Statement


Do you think a meter will handle an a.c. current of any frequency?


Homework Equations





The Attempt at a Solution


Since we can illustrate an ammeter as a moving coil with a resistor in parallel, and since all elements in a circuit will exhibit inductive and capacitive behavior when the frequency is any other than 0 Hz, the impedance across the parallel resistor will increase with increasing frequency as the inductive reactance increases (X_L = \omega L) (while the capacitive reactance nears 0), so more and more current will bypass the shunt resistor and go straight through the moving coil of the ammeter and this could clip it (?).

Though, since the moving coil also has *some* resistance, this will also have increasing impedance with increasing frequency, so the above might not hold?
 
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The moving coil has a lot more resistance than the shunt resistor.

If you regard the resistance of the coil as being in series with the coil and assume the resistances do not change, and assume the total current does not change...then what happens to the impedance of the coil at higher frequencies?

Remembering current division, how does the current split up at higher frequencies?

What effect will this have on the meter reading?

Is there a very simple way to avoid this problem?
 

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