Amount of energy rerquired to raise temperature

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Homework Help Overview

The discussion revolves around calculating the amount of energy required to raise the temperature of 12.0 kg of water from 0 degrees Celsius to 25 degrees Celsius, utilizing the specific heat capacity of water.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants present different methods for calculating energy, including the formula Q = m*c*ΔT and an alternative approach using grams and calories. Questions arise regarding the appropriateness of units (joules vs. calories) for the final answer.

Discussion Status

The discussion includes various methods and considerations regarding unit conversions. Participants express uncertainty about the correct units for the answer and explore the implications of different calculation methods without reaching a definitive conclusion.

Contextual Notes

There is a mention of the specific heat capacity for water and the conversion between joules and calories, but no consensus on the preferred units for the final result has been established.

chaotiiic
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Homework Statement


What amount of energy is required to raise the temperature of 12.0 kg of water
from 0 degrees Celsius to 25 degrees Celsius?


Homework Equations


Q = m*c*ΔT
1 calorie = 4.186J
specific heat capacity for water = 4.19x10^3


The Attempt at a Solution


Q = m*c*ΔT = (12kg)(4.19x10^3)(25°) = 1,257,000J
1257000J/4.186 = 300,286 calories
 
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chaotiiic said:

Homework Statement


What amount of energy is required to raise the temperature of 12.0 kg of water
from 0 degrees Celsius to 25 degrees Celsius?


Homework Equations


Q = m*c*ΔT
1 calorie = 4.186J
specific heat capacity for water = 4.19x10^3


The Attempt at a Solution


Q = m*c*ΔT = (12kg)(4.19x10^3)(25°) = 1,257,000J
1257000J/4.186 = 300,286 calories

Did you have a question about your method or result?
 
gneill said:
Did you have a question about your method or result?
both.
another method i found online was to do (12000grams)*1cal/(g*K)*25 = 300,000 calories which is close to my first result. also i wasnt sure if the answer should be in joules or calories.
 
chaotiiic said:
both.
another method i found online was to do (12000grams)*1cal/(g*K)*25 = 300,000 calories which is close to my first result. also i wasnt sure if the answer should be in joules or calories.

Both methods amount to the same thing. As for the units of the result, that depends upon who is asking the question and what units they expect the answer to be in :smile: The calorie is a unit of energy, as is the Joule.
 
gneill said:
Both methods amount to the same thing. As for the units of the result, that depends upon who is asking the question and what units they expect the answer to be in :smile: The calorie is a unit of energy, as is the Joule.
ok thanks
 

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