- #1
AJKing
- 104
- 2
Homework Statement
A simple pendulum has a length of 1m. In free vibration the amplitude of its swings falls off by a factor of e in 50 swings. The pendulum is set into forced vibration by moving its point of suspension horizontally in SHM with an amplitude of 1 mm.
a) [... Built Differential ...]
b) [... Found Amplitude at exact resonance = 0.1576m ...]
c) At what angular frequencies is the amplitude half of its resonant value?
Homework Equations
[itex]A_m = 0.1576 m[/itex]
[itex]F/m = \frac{gζ}{l}[/itex]
Let ζ = amplitude of driver.
[itex]Q= 50 π[/itex]
[itex]A(ω) = \frac{F/m}{((ω_0^2 - ω^2)^2 + (γω)^2)^{0.5}}[/itex]
The Attempt at a Solution
Solution is exactly stated as: "ω0 ± 0.017 sec-1"
Am I solving for ω or ω0?