- #1

nehcrow

- 15

- 0

and you have the following information: A 200 g block hangs from a spring with spring constant 10 N/m. At t = 0s the block is 20 cm below the equilibrium position and moving upward with a speed of 100 cm/s.

The answers give a short method of calculating the amplitude but I have no idea how the reached it, basically what they did was: A = sqrt((x0)^2 + (v0/ω)^2)

how did they reach that conclusion??