If it's a Bell inequality using only the matrices defined in the beginning of this thread that you want, then a simple one depending only on ##E## and ##F## is $$- \bar{E} + 3 \bar{F} \leq 2 \,, \qquad (*)$$ with $$\begin{eqnarray*}
\bar{E} &=& E_{00} - E_{01} - E_{10} + E_{11} \,, \\
\bar{F} &=& F_{00} - F_{01} - F_{10} + F_{11} \,.
\end{eqnarray*}$$ This is taking results from the different measurement settings to contribute equally to ##E## and ##F##, i.e., in terms of the conditional probabilities, $$\begin{eqnarray*}
E_{ab} &=& \frac{1}{3} \sum_{x} P(ab \mid xx) \,, \\
F_{ab} &=& \frac{1}{6} \sum_{x \neq y} P(ab \mid xy)
\end{eqnarray*}$$ for ##a, b \in \{0, 1\}## and ##x, y \in \{0, 1, 2\}##. (The simplest way to ensure this is just to make this the definition of the matrices ##E## and ##F##.) Otherwise, the inequality holds under the same sort of assumptions as other Bell inequalities, e.g., if you don't do any postselection or you make the fair sampling hypothesis.
I'll skip the details on how (*) was derived unless someone asks. In any case, with (*) given it's not especially difficult to check that it must hold for any LHV. Using a state and measurements similar to those that maximally violate the 1964 Bell inequality it's possible to have ##\bar{E} = -1## and ##\bar{F} = 1/2##, so QM can attain at least ##- \bar{E} + 3 \bar{F} = 2.5##, which violates (*). Finally, since ##\lvert \bar{E} \rvert, \lvert \bar{F} \rvert \leq 1##, the algebraic bound is ##- \bar{E} + 3 \bar{F} \leq 4##, and there's a ##3 \times 3##-measurement version of the PR box that can attain this while still respecting the no-signalling principle. So if you want a function of value between 0 and 1 when it detects Bell-nonlocal correlations then one possibility is $$W = -1 + \frac{- \bar{E} + 3 \bar{F}}{2} \,.$$