An electron is released from rest in a uniform electric field

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To determine the magnitude of the electric field affecting an electron released from rest, the equation s = a t^2/2 is used, where s is the distance traveled, a is the acceleration, and t is the time. Given that the electron travels 4.50 m in 3.00 microseconds, the acceleration can be calculated using this formula. The electric field can then be found using the relationship between acceleration and electric force, which is derived from Newton's second law and the charge of the electron. The discussion emphasizes the importance of understanding the relationship between distance, time, and acceleration in the context of electric fields. This approach provides a clear pathway to solving the problem.
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I need help with this question if anyone can give me an idea of what to do. Any help would be greatly appreciated.

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in the first 3.00 micro seconds after it is released.
What is the magnitude of the electric field?
 
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HINT: s = a t^2/2
 

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