An interesting coupled oscillators problem (multiple springs and masses)

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SUMMARY

The discussion centers on deriving the differential equations for a system of coupled oscillators involving multiple springs and masses. The equations presented include kΔy - mg = m(d²y₂/dt²) and -2kΔy₁ - kΔy₂ - 2mg = m(d²y₁/dt²). Participants highlight the need for consistent units across the equations and suggest breaking down the problem into smaller steps to clarify the forces acting on each mass. The importance of correctly identifying variables and their relationships is emphasized to avoid confusion in the derivation process.

PREREQUISITES
  • Understanding of Newton's second law (ΣF = ma)
  • Familiarity with differential equations
  • Knowledge of spring constants and Hooke's law
  • Basic concepts of oscillatory motion
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  • Study the application of Newton's laws to systems of masses and springs
  • Learn about consistent unit analysis in physics equations
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mliempi2018
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Homework Statement
Waves and oscillations
Relevant Equations
2nd Newton's Law.
Sin título.png

I need to find the differential equations for each mass. ##y_1## is the equilibrium position, and ##y_2## is the second equilibrium position for each mass.
I was thinking consider the next sistem:

\begin{eqnarray}
k\Delta y-mg&=&m\frac{d^2 y_2}{dt^2}
\\ -2k\Delta y_1 -k\Delta y_2 -2mg &=&m\frac{d^2 y_1}{dt^2}
\end{eqnarray}

But I'm not sure , anybody can help me please??
 
Last edited:
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mliempi2018 said:
\begin{eqnarray}
y_2 (t) &=& k\Delta y-mg=m\frac{d^2 y_2}{dt^2}
\\ y_1(t)&=& -2k\Delta y_1 -k\Delta y_2 -2mg =m\frac{d^2 y_1}{dt^2}
\end{eqnarray}
I don’t understand the ##y_1 (t)=## and ##y_2 (t)=##. Do you mean "For ##y_1##:" etc?
What is "y" in the ##k\Delta y## in ##k\Delta y-mg=m\frac{d^2 y_2}{dt^2}##?
 
And for me, the units do not match in these equations (position units versus force units?)

1593297692082.png
 
\begin{eqnarray}
\Delta y
\end{eqnarray}
is the variation of each spring, and k is the resort constant,, and I'm sorry, y_1 is the solution, it is my mistake.
 
mliempi2018 said:
\begin{eqnarray}
\Delta y
\end{eqnarray}
is the variation of each spring, and k is the resort constant,, and I'm sorry, y_1 is the solution, it is my mistake.
No worries. Can you re-write your differential equations so the units are consistent? That will help a lot in moving forward. Thanks. :smile:
 
mliempi2018 said:
\begin{eqnarray}
\Delta y
\end{eqnarray}
is the variation of each spring, and k is the resort constant,, and I'm sorry, y_1 is the solution, it is my mistake.
But you wrote ##k\Delta y-mg=m\frac{d^2 y_2}{dt^2}##. So you have ##k\Delta y## on the left but ##y_2## on the right. So presumably you meant ##k\Delta y_2-mg=m\frac{d^2 y_2}{dt^2}##, yes?
But that is incorrect. The length of the middle spring is ##y_1-y_2##, so the variation in its length is the variation in that expression.
Your second equation has several errors. I feel you have jumped straight into writing the differential equations when you would do better to take it in smaller steps. Write variables for the forces in the springs, and write the ##\Sigma F=ma## equation for each mass in terms of those forces and the force of gravity on that mass.
 
Hi! does this exercise come from a book?
 

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