Sorry, I don't have seen your example yet, anyway, concerning the transformation from a ref. frame where both particle 1 and particle 2 have non zero velocity, I find, instead of equation (33) of "Introduction to Relativistic Collisions":...
For point 2 I would refer you to the worked example where the pre-collision mass is that of the two colliding protons and the post-collision mass is that of the two protons plus the 'generated' kaons.
Only a last comment on the title of this insight, Neil (by the way, from your nickname it seems we have the same age): if energy is always conserved, how can it "generate" something else ("mass")?...
Energy cannot be "generated", only transformed or converted. Your exampEnergy is neither created nor destroyed - simply changed from one form to another. I think that would apply to just about any form of energy 'generation'. In a nuclear power plant we generate energy from mass, here we generate mass from energy.
Something went wrong here. The phrase should have been:Energy cannot be "generated", only transformed or converted. Your examp
Not explicitly no. But I did indicate somewhere in the article that in the Lorentz factor ##\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}## the 'v' was to be taken as a relative velocity in which case ##T_2=0##.Sorry, I don't have seen your example yet, anyway, concerning the transformation from a ref. frame where both particle 1 and particle 2 have non zero velocity, I find, instead of equation (33) of "Introduction to Relativistic Collisions":
##{E_3^0}^2={E_1^0}^2+{E_2^0}^2+2E_1^0 E_2^0+2T_1E_2^0+2T_1T_2+2T_2E_1^0-2c^2\vec{p_1}·\vec{p_2}## (*)
Then we change frame on K', co-moving with particle 2; ##\vec{v_1}'## is now the relativistic relative velocity between particle 1 and particle 2 and:
##T_2'=\vec{p_2}'=0##
so (*) becomes equal to (33).
I apologize if you have already described this in your last example.
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