An object oscillating in simple harmonic motion

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SUMMARY

The discussion centers on an object oscillating in simple harmonic motion (SHM) with a period of T = 3.6s. The calculations for amplitude (A) and maximum acceleration (a_max) were initially misunderstood, with the correct values being A = 2.8m and a_max = 0.52 m/s², which require a period of T = 14.4s to be accurate. The confusion arose from the misinterpretation of the maximum velocity occurring at the central position, which happens twice per period. Clarification on the wording of the problem statement is also suggested to avoid ambiguity.

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lorenz0
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Homework Statement
An object oscillates in simple harmonic motion, reaching a maximum velocity of ##1.2m/s## whenever it passes through the central position, which occurs every ##3.6s##.
Find the amplitude and maximum acceleration of the harmonic motion.
Relevant Equations
##v_{max}=\omega A##, ##a_{max}=\omega^2 A##, ##\omega=\frac{2\pi}{T}##
Since it passes through the origin every ##3.6s## the period is ##T=3.6s## hence ##\omega=\frac{2\pi}{\omega}=\frac{2\pi}{3.6}\frac{rad}{s}## thus ##A=\frac{v_{max}}{\omega}=\frac{1.2}{\frac{2\pi}{3.6}}m\simeq 0.69m## and ##a_{max}=\omega^2 A=(\frac{2\pi}{T})^2 A=(\frac{2\pi}{3.6})^2 \cdot 0.69\simeq 2.1\frac{m}{s^2}##.

What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
 
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lorenz0 said:
Since it passes through the origin every ##3.6s## the period is ##T=3.6s##
It passes through the origin twice per period!
 
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Start with a sketch of a generic SHM and label the times of the zero-crossings:

1638717577675.png
 
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lorenz0 said:
What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
These don't look right to me. Especially the acceleration, which looks very low.
 
lorenz0 said:
What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
To get those answers you need the period to be ##14.4s##.
 
PeroK said:
It passes through the origin twice per period!
Ah, I understand my mistake now, thanks!
 
lorenz0 said:
Homework Statement:: An object oscillates in simple harmonic motion, reaching a maximum velocity of ##1.2m/s## whenever it passes through the central position, which occurs every ##3.6s##.
That's a poorly worded statement. The oscillator will pass through the central position twice per period, but will have a maximum velocity only once per period. The statement can be fixed by specifying that it reaches a maximum speed of 1.2 m/s whenever it passes through the central position.
 

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