An object oscillating in simple harmonic motion

Click For Summary

Homework Help Overview

The discussion revolves around an object oscillating in simple harmonic motion (SHM), specifically focusing on its period, amplitude, and maximum acceleration. Participants are analyzing the implications of the object's motion as it passes through the origin and the associated parameters of SHM.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to reconcile their calculations of amplitude and maximum acceleration with provided solution values. There is a focus on understanding the implications of the period and the nature of zero-crossings in SHM. Questions arise regarding the wording of the problem statement and its impact on interpretation.

Discussion Status

There is active engagement with differing interpretations of the problem statement and the calculations involved. Some participants have identified potential misunderstandings regarding the frequency of zero-crossings and maximum velocity, while others are seeking clarification on the correct values for amplitude and maximum acceleration. No consensus has been reached, but the discussion is exploring various angles.

Contextual Notes

Participants note that the problem statement may be misleading, particularly regarding the maximum velocity and its occurrence in relation to the central position. There is also mention of the need for clarity on the period of oscillation, which affects the derived parameters.

lorenz0
Messages
151
Reaction score
28
Homework Statement
An object oscillates in simple harmonic motion, reaching a maximum velocity of ##1.2m/s## whenever it passes through the central position, which occurs every ##3.6s##.
Find the amplitude and maximum acceleration of the harmonic motion.
Relevant Equations
##v_{max}=\omega A##, ##a_{max}=\omega^2 A##, ##\omega=\frac{2\pi}{T}##
Since it passes through the origin every ##3.6s## the period is ##T=3.6s## hence ##\omega=\frac{2\pi}{\omega}=\frac{2\pi}{3.6}\frac{rad}{s}## thus ##A=\frac{v_{max}}{\omega}=\frac{1.2}{\frac{2\pi}{3.6}}m\simeq 0.69m## and ##a_{max}=\omega^2 A=(\frac{2\pi}{T})^2 A=(\frac{2\pi}{3.6})^2 \cdot 0.69\simeq 2.1\frac{m}{s^2}##.

What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
 
Physics news on Phys.org
lorenz0 said:
Since it passes through the origin every ##3.6s## the period is ##T=3.6s##
It passes through the origin twice per period!
 
  • Like
Likes   Reactions: lorenz0
Start with a sketch of a generic SHM and label the times of the zero-crossings:

1638717577675.png
 
  • Like
Likes   Reactions: lorenz0
lorenz0 said:
What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
These don't look right to me. Especially the acceleration, which looks very low.
 
lorenz0 said:
What I have done makes sense to me so I don't understand why the solutions to this problem state that ##A=2.8m## and ##a_{max}=0.52\frac{m}{s^2}##. Comment are welcome, thanks.
To get those answers you need the period to be ##14.4s##.
 
PeroK said:
It passes through the origin twice per period!
Ah, I understand my mistake now, thanks!
 
lorenz0 said:
Homework Statement:: An object oscillates in simple harmonic motion, reaching a maximum velocity of ##1.2m/s## whenever it passes through the central position, which occurs every ##3.6s##.
That's a poorly worded statement. The oscillator will pass through the central position twice per period, but will have a maximum velocity only once per period. The statement can be fixed by specifying that it reaches a maximum speed of 1.2 m/s whenever it passes through the central position.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
1K
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
7
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
31
Views
2K
Replies
16
Views
2K
  • · Replies 51 ·
2
Replies
51
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K