Analogue Circuits Question -- AC and DC currents through a coil

  • #1
38
7
Summary:: .

Hi ,so am currently doing homework , and was wondering if anyone could tell me if i have done my calculations correctly ,because am not 100% sure that i have answer to those 2 questions correctly .If i have went somewhere wrong if you could tell me where and how i could fix it ,that would be great. Thank you.
 

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Answers and Replies

  • #2
Your capacitive reactance answer looks good.
 
  • #3
You are a bit more consistent than the examiner.
The questioner wrongly specifies lower case units, without a space; 100v, 250w, 50hz.

For units named after a person, such as Volta, Watt or Hertz;
the initial should be spaced and upper case; 100 V, 250 W, 50 Hz;
while the spelled out unit should be all lower case; 100 volt, 250 watt, 50 hertz.
 
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Likes berkeman and IronaSona
  • #4
Both answers contain typos.
The answer for the capacitor case looks ok, though I haven't check the arithmetic operations.

The answer for the coil contains too many typos and inconsistencies, for example you write that ##Z=\sqrt{R^2+X_L^2}## and then later you seem to imply that ##Z=X_L##.

Please rewrite the answer for the coil.
 
  • #5
Both answers contain typos.
The answer for the capacitor case looks ok, though I haven't check the arithmetic operations.

The answer for the coil contains too many typos and inconsistencies, for example you write that ##Z=\sqrt{R^2+X_L^2}## and then later you seem to imply that ##Z=X_L##.

Please rewrite the answer for the coil.
is this better ?
 

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  • #6
Nope you basically do the same mistake. The correct way to go is as follows:
The coil's impedance at 60hz is ##Z=\frac{140}{2}##. Use this and the equation ##Z=\sqrt{R^2+X_L^2}## to correctly determine the reactance ##X_L## at 60 hz and from that the value of L.
Then you should NOT forget the ohmic resistance of the coil when you calculate the new reactance and new impedance at 50hz
 
  • #7
Nope you basically do the same mistake. The correct way to go is as follows:
The coil's impedance at 60hz is ##Z=\frac{140}{2}##. Use this and the equation ##Z=\sqrt{R^2+X_L^2}## to correctly determine the reactance ##X_L## at 60 hz and from that the value of L.
Then you should NOT forget the ohmic resistance of the coil when you calculate the new reactance and new impedance at 50hz
 

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  • #8
There are still some typos but now what you do seems correct. Havent checked the arithmetic.
 

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