Analyzing Acceleration of Wedge and Block System

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SUMMARY

The discussion focuses on analyzing the acceleration of a block sliding down a frictionless inclined plane of a wedge, with the wedge itself on a horizontal surface with a coefficient of friction (u). The derived acceleration of the wedge is expressed as g(1-3u)/(3-u). Key steps include drawing free body diagrams (FBDs) for both the block and the wedge, applying Newton's second law (F=ma) in both vertical and horizontal directions, and recognizing the relationship between the accelerations of the block and the wedge to maintain contact.

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  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams (FBDs)
  • Knowledge of friction coefficients and their effects on motion
  • Basic principles of inclined planes in physics
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  • Study the derivation of acceleration in systems involving inclined planes and wedges
  • Learn about the effects of friction on motion, specifically in multi-body systems
  • Explore advanced applications of Newton's laws in non-linear motion scenarios
  • Investigate the principles of contact forces in dynamic systems
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Homework Statement


A block m slides from frictionless inclined (45 with horizontal (a)) of a wedge mass m which on horizontal plane with coefficient of friction u. Prove the wedge moves to right with acc. equal to g(1-3u)/(3-u)

Homework Equations


The Attempt at a Solution


block has normal reaction mgcos (a) ...
then...
 
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I don't see my way through to the end yet, but certainly you must begin by drawing the free body diagrams for the block and the wedge. No friction force for the wedge on the block (or vice versa) so I guess the force of the block on the wedge (and vice versa) will be perpendicular to the wedge surface. Once you have the FBDs, write the vertical and horizontal F = ma for each body and hopefully you'll be able to solve for the acceleration you are looking for! Don't be afraid to start even when the end isn't in sight.
 
Oh, it was tough thinking! I didn't have enough equations and started thinking about the fact that the block stays in contact with the wedge as it accelerates down. But the horizontal acceleration of the block is not the same as that of the wedge, because the block is changing its horizontal position with respect to the center of mass of the wedge. Finally ended up with a huge simplification by switching to the direction perpendicular to the wedge when working on the block's forces. The acceleration of the block in that direction must be the same as the component of the wedge's acceleration in that direction - in order to keep them in contact.
 

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