Analyzing Frictionless Motion: Va vs Vb

In summary, the problem involves two masses connected by a pulley and moving in a frictionless environment. The velocity of one mass, Va, is initially greater than the velocity of the other mass, Vb, but as time passes the velocity of Vb increases and becomes greater than Va. The problem may require a diagram for better understanding.
  • #1

Homework Statement

va=va vb=vb m1>m2

Homework Equations

The Attempt at a Solution

So i got this question where m1 is on a table and connected to a pully and m2 is hanging off the table, which have a Va (velocity). Then a few seconds later the pully is drawing in and the distance from m1 and the pully decreases, basically the pully is going down. This was considered Vb(velocity). The instructor asked us which had more velocity or did it stay the same, my intution is telling me that the velocity increased but through energy of conservation I feel like it stayed constant and went to the hanging mass. I have no idea, I already took the quiz and just want some reassurance on whether i was right or wrong >_<
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  • #2
Welcome to PF!
I'd like to help, but I just don't understand the question as written. Actually a diagram is pretty much necessary to sort out pulley problems.
  • #3
I agree a diagram would be helpful... From my understanding of the problem is that you have two masses connected via a pulley, one of the masses is on a table (assuming the table is not angled...) and the other mass is hanging freely.

It sounds to me like you are asking if V(t) is increasing so assuming that is actually the problem then Vb is greater than Va since the table is frictionless and you have a constant acceleration due to gravity.