Exploring Oscillatory Motion of Two Connected Masses on a Frictionless Track

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Homework Help Overview

The discussion revolves around the oscillatory motion of two masses connected by a spring on a frictionless track. Participants are exploring the dynamics of the system, particularly focusing on the force equations and equilibrium conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the force equation and the conditions for equilibrium in the context of oscillatory motion. Questions are raised about the nature of the forces involved when the masses are at different separations relative to the equilibrium position. There is also discussion about the definitions of variables and the setup of the equations.

Discussion Status

The discussion is ongoing, with participants clarifying their understanding of the equations and their implications. Some have identified relevant equations and are working through the mathematical relationships, while others express confusion about the definitions and the physical interpretation of the setup.

Contextual Notes

There are indications of missing information regarding the definitions of variables and the setup of the problem. Participants are questioning assumptions about the equilibrium position and the nature of the forces acting on the masses.

grandpa2390
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Homework Statement


Two masses slide freely in a horizontal frictionless track and are connected by a Spring whose force constant is k. Fid the frequency of oscillatory motion for this system.

Homework Equations


My professor posted the solution but I am having trouble understanding everything that he did.
according to the solution, the first step is defining the Force equation as
F = -k(x2 - x1 - deltaXe) where deltaXe is the equilibrium separation. x1 is the distance to the center of mass of m1 from some point to the left of m1. x2 is the distance from that point to the center of m2. so that x2-x1 equals the distance between the center of m1 and m2.

The Attempt at a Solution


the distance between the atoms at which the force on each atom is zero. Is the force repulsive (atoms are pushed apart) or attractive (atoms are pulled together) if their separation is (b) smaller and (c) larger than the equilibrium separation
is this the distance between the two masses when the spring is neither compressed nor stretched? Wouldn't that just be x2-x1? so the the Force would be 0?
 
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and then later on in the solution he takes says that dXe is equal to x2e - x1e (x2e = the distance of m2 from the center of the spring during equilibrium and likewise with x1e) shouldn't dXe = x2e + x1e ?
 
My professor posted the solution but I am having trouble understanding everything that he did
Doesn't look like a relevant equation to me. Don't you have a few things that look like

##m_1\ddot x_1 = - F_s##

##m_2\ddot x_2 = F_s##

## F_s = -k (x_2 - x_1 - \Delta x_{eq})##
so that we can do some mathematics on them ?

Because in that case we could easily derive

##m_1\ddot x_1 + m_2\ddot x_2 =0##

and concentrate on

##m_1 \ddot x_1 - m_2 \ddot x_2 + 2k( x_2 - x_1 - \Delta x_{eq})=0## ?

And perhaps the masses happen to be equal ? Saves work and yields a pleasant answer.

Then: In your attempt there is the sudden appearance of atoms that weren't there before. Please read what you wrote as if you were a helper trying to make sense of your post. I am one and I can't.
 
that third equation is the one. I figured out what it was. the origin was defined in the middle of the spring. So that x1 is negative. so it does turn out right.
 

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