Nicolaus
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Homework Statement
- ut +ux = 0 subject to u(t,x) = x on x^2 + y^2 = 1
Is this a well-posed PDE BVP?
Homework Equations
The Attempt at a Solution
This is an easy one to solve: u(t,x) = f(x-t)
I let t(0) = 0 as an initial condition, and so t=s => x= ts + xo, where x(0) = xo
s is the variable such that ∂(u(t(s), x(s))/∂s = 0
If I let u(t,x) = x = f(x-t), would this not be well-posed since f must be a function of (x-t)?