Analyzing Relativistic Effects on Low-Flying Satellites

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SUMMARY

The discussion focuses on the relativistic effects experienced by a low-flying Earth satellite traveling at approximately 8000 m/s. The relativistic factor, represented by $$\gamma = \frac{1}{\sqrt{1-\beta^2}}$$, where $$\beta = \frac{v}{c}$$, is evaluated using both direct calculation and Taylor series expansion. The calculations yield a value of $$\gamma \approx 1.00000000036$$, indicating minimal deviation from 1 due to the satellite's low velocity compared to the speed of light. The conversation highlights the importance of precision in numerical calculations and the limitations of calculators in providing significant digits.

PREREQUISITES
  • Understanding of relativistic physics concepts, specifically the Lorentz factor.
  • Familiarity with Taylor series expansions and their applications in physics.
  • Proficiency in using scientific calculators, such as the TI-89, for high-precision calculations.
  • Basic knowledge of the speed of light and its significance in relativistic calculations.
NEXT STEPS
  • Explore advanced applications of the Lorentz factor in high-speed particle physics.
  • Learn about the implications of relativistic effects in satellite technology and GPS systems.
  • Investigate numerical methods for increasing precision in scientific calculations.
  • Study the effects of varying velocities on relativistic calculations, particularly at speeds closer to the speed of light.
USEFUL FOR

Students and professionals in physics, aerospace engineering, and satellite technology who are interested in understanding relativistic effects and their practical implications in low-speed scenarios.

mch
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Homework Statement


[/B]
A low flying Earth satellite travels at about 8000m/s. For the satellite, the relativistic factor $$\gamma = \frac{1}{\sqrt{1-\beta^2}}$$ where $$\beta = \frac{v}{c}$$ is close to 1 because v<<c. Estimate by how much gamma actually deviates from 1 by expanding gamma in a taylor series and evaluating all terms up to second order.

Homework Equations

The Attempt at a Solution


[/B]
To be sure, I plugged in 8000 for v in gamma originally. That is, I evaluated $$\gamma = \frac{1}{\sqrt{1-\beta^2}}$$ with $$\beta = \frac{8000}{3\times10^8}$$ When I put this gamma into my TI-89 and used 12-point-float, it came back with 1.00000000036. This makes sense, since the satellite is moving so slow compared to the speed of light. However, when I did the taylor expansion, I came up with $$\gamma \approx 1 + \frac{\beta^2}{2}$$ and when I put in the aforementioned beta value, i came up with the EXACT same value as before. So my question is a semantic one I suppose: what is the question wanting me to do? How can I get a more useful number when both "techniques" yield the same number?
 
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mch said:

Homework Statement


[/B]
A low flying Earth satellite travels at about 8000m/s. For the satellite, the relativistic factor $$\gamma = \frac{1}{\sqrt{1-\beta^2}}$$ where $$\beta = \frac{v}{c}$$ is close to 1 because v<<c. Estimate by how much gamma actually deviates from 1 by expanding gamma in a taylor series and evaluating all terms up to second order.

Homework Equations

The Attempt at a Solution


[/B]
To be sure, I plugged in 8000 for v in gamma originally. That is, I evaluated $$\gamma = \frac{1}{\sqrt{1-\beta^2}}$$ with $$\beta = \frac{8000}{3\times10^8}$$ When I put this gamma into my TI-89 and used 12-point-float, it came back with 1.00000000036. This makes sense, since the satellite is moving so slow compared to the speed of light. However, when I did the taylor expansion, I came up with $$\gamma \approx 1 + \frac{\beta^2}{2}$$ and when I put in the aforementioned beta value, i came up with the EXACT same value as before. So my question is a semantic one I suppose: what is the question wanting me to do? How can I get a more useful number when both "techniques" yield the same number?
They're not exactly the same value. They're only the same to the number of digits that your calculator has provided. If it could provide more digits (without roundoff), the numbers would be different. How would you calculator do if the velocity was only 1 meter per second? How would your approximate equation do?

Chet
 

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