Angle between colors - dispersion

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    Angle Dispersion
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SUMMARY

The discussion focuses on calculating the angle between yellow (660nm) and green (550nm) wavelengths of light as they transition from polystyrene to air at a 30-degree incident angle using Snell's Law. Participants confirm the necessity of knowing the refractive indices for each wavelength, which are approximately 1.492 for yellow and 1.493 for green. The correct angle of separation between the colors upon emergence is determined to be 0.043 degrees, and the distance required for them to be separated by 1.00 mm is calculated to be 1.33 meters.

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  • Understanding of Snell's Law of refraction
  • Knowledge of refractive indices for different wavelengths
  • Basic trigonometry for angle calculations
  • Familiarity with light wavelength measurements (e.g., nanometers)
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BDR
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(a) A narrow beam of light containing yellow (660nm) and green (550nm) wavelengths goes from polystyrene to air, striking the surface at a 30 degree incident angle. What is the angle between the colors when they emerge? (b) How far would they have to travel to be separated by 1.00 mm?

I need some guidance on if i am working the problem right! Do i use Snell's Law?

1.49sin30 = 1.000293sin(angle)?
 
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Yes, use Snell's law of refraction. But you need to know the refractive index for each wavelength. The angle of incidence is the same (30 degrees), but the angle of refraction will be slightly different for each wavelength.
 
Here is what I'm doing!

Yellow: 1.492sin(30) = 1.000293sinθ

Green: 1.493sin(30) = 1.000293sinθ

When I do the calculations i am not getting the correct. The answer is suppose to be 0.043 degrees and 1.33 m. Where do you think I am messing up the calculations?
 
Beats me since you didn't show your calculations!

Using those same equations I get 0.043 degrees, so I'm not sure where you went wrong. Try this: (1) Solve for the angle of refraction for each color; (2) Subtract those angles to find the angle between the two refracted colors.
 

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