Angle between vector and z-axis

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The discussion focuses on finding the angle between the normal vector to a surface and the z-axis in a specific homework problem. The normal vector is identified as the gradient of the surface equation. The angle is calculated using the dot product and cosine relation, specifically with the vector (0,0,1) representing the z-axis. Participants express frustration over the lack of clarity in the problem presentation and emphasize the need for clear text rather than images. The conversation highlights the importance of proper formatting and clarity in problem-solving discussions.
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1. Homework Statement


I am looking at problem 2.2 pictured above.
I have solved all portions of the question except the last part, which asks for the angle between the normal vector to the surface and the z-axis.
I am aware that the normal vector is simply equal to the gradient of the surface given (the L.H.S. of the equation in the second line of the problem statement. In order to find the angle between this normal and the z-axis (for which I am using the vector (0,0,1), I am using the familiar dot product-cosine relation: a•b = |a| |b| cos(x)

Homework Equations

The Attempt at a Solution

 
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Syrus said:
View attachment 110018 1. Homework Statement

I am looking at problem 2.2 pictured above.
I have solved all portions of the question except the last part, which asks for the angle between the normal vector to the surface and the z-axis.
I am aware that the normal vector is simply equal to the gradient of the surface given (the L.H.S. of the equation in the second line of the problem statement. In order to find the angle between this normal and the z-axis (for which I am using the vector (0,0,1), I am using the familiar dot product-cosine relation: a•b = |a| |b| cos(x)

Homework Equations

The Attempt at a Solution


Do not post images (especially do not post them sideways!). Just type out the problem; it is simple enough and does not need a lot of work.
 
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Anyone care to provide a meaningful response?
 
Not me. I'm not willing to lie down to read it.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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