(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

This is a problem involving parametric equations.

r_{1}= <t,2-t,12+t^{2}>

r_{2}= <6-s,s-4,s^{2}>

At what point do the curves intersect?

Find the angle of intersection, to the nearest degree.

3. The attempt at a solution

I found the point of intersection, (2,0,16). This is when t=2 and s=4.

I found the tangent vectors.

d/dt(r1) = <1,-1,2t>

d/ds(r2) = <-1,1,2s>

I used r_{1}[itex]\cdot[/itex]r_{2}= |r1||r2|cos[itex]\theta[/itex], using the tangent vectors at t=2 and s=4, and solved for theta.. I came up with 23°, but the system tells me I'm wrong. What happened?

EDIT:: Okay.... it seems like I was coming up with a different answer every time. Got it on my last try though. Gotta be more careful... for anyone wondering, the correct answer is 29°

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# Angle of intersection between two parametric curves

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