So I already have x=(1/y)-y^2 and y=t and therefore x=(1-t^2)/t. Then z=(1-2t)/t^2. Is this the parametrization? If so, I have been sitting here for hours trying to find a trig relationship. It just looks too simple.Solve easily for x=f(y). Paremetrization will be y=t, x=f(t).
Wait, so am I thinking about my parametrization wrong? Can I not define x, y, and z in terms of parameter t? In what ways is my answer wrong for my parametrization? I'm sorry if I'm asking so many quick questions but I really would like to understand this concept. So I had solved to x(t), y(t), and z(t) by manipulating the equations of two surfaces, z=x^2-y^2 and z=x^2+xy-1, and from this is gained a parametrization of x(t)=(1-t^2)/t, y(t)=t, and z(t)=(1-2t)/t^2 and I write this as r(t)=<x(t),y(t),z(t)> which is defined when t does not equal 0. Thank you for all your help so far.The parametrization of a curve is done with 1 variable t, but the parametrization of a surface needs 2 variables.
So this form I found is a good final form? I feel like I'm missing something? Thank you for everything! If this is true I can finally sleep before work!Ok i just thought you were trying to parametrize the surface z=... but i see now what you were after.