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Calculating the Angle Between Virtual Sources of Fresnel's Biprism
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[QUOTE="Steve4Physics, post: 6643170, member: 681522"] The formula (using your symbols) for the separation between the sources is really: ##d = 2(\mu – 1) sin(\alpha) y_1##. But since ##\alpha## is small, we can use the small angle approximation. There is very little difference between the values of ##sin(\alpha)## and ##\alpha## in radians. ##2º = 2 \times \frac {\pi}{180}## radians ##= \frac {\pi}{90}## radians ##= 0.0349## radians ##sin(2º) = 0.0349## (Check it for yourself on a calculator.) So we simplify the above formula to: ##d = 2(\mu – 1) \alpha y_1##. By the way, the working in your attachment has a mistake. It says: ##d = \frac {2(1.5 – 1) \times 10} {90} = ...## but it should say: ##d = \frac {2(1.5 – 1) \times \pi \times 10} {90} = ...## [/QUOTE]
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Calculating the Angle Between Virtual Sources of Fresnel's Biprism
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